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11th Standard English Medium Maths Subject Introduction To Probability Theory Creative 1 Mark Questions with Solution Part - I

11th Standard

    Reg.No. :
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Maths

Time : 01:00:00 Hrs
Total Marks : 5

    1 Marks

    5 x 1 = 5
  1. The probabilities of a student getting I. II and III class in an examination are \(\frac { 1 }{ 10 } ,\frac { 3 }{ 5 } \) and \(\frac { 1 }{ 4 } \) respectively. The probability that the student fails in the examination is

    (a)

    \(\frac { 197 }{ 200 } \)

    (b)

    \(\frac { 27 }{ 100 } \)

    (c)

    \(\frac { 83 }{ 100 } \)

    (d)

    none of these

  2. Three integers are chosen at random from the first 20 integers. The probability that their product is even is

    (a)

    \(\frac { 2 }{ 19 } \)

    (b)

    \(\frac { 3 }{ 19 } \)

    (c)

    \(\frac { 17 }{ 19 } \)

    (d)

    \(\frac { 4 }{ 19 } \)

  3. The probability that in a year of 22nd century, chosen at random there will be 53 Sundays is

    (a)

    \(\frac { 3 }{ 28 } \)

    (b)

    \(\frac { 2 }{ 28 } \)

    (c)

    \(\frac { 7 }{ 28 } \)

    (d)

    \(\frac { 5 }{ 28 } \)

  4. If A and B are two events such that \(P(A\cap B)=\frac { 7 }{ 10 } \) and P(B) = \(\frac { 17 }{ 20 } \) , then P(A/B) =

    (a)

    \(\frac { 14 }{ 17 } \)

    (b)

    \(\frac { 17 }{ 20 } \)

    (c)

    \(\frac { 7 }{ 8 } \)

    (d)

    \(\frac { 1 }{ 8 } \)

  5. Let A and B be two events such that P(A) = 0.6, P(B) = 0.2 and P(A/B) = 0.5, Then P(\(\bar { A } /\bar { B } \)) is

    (a)

    \(\frac { 1 }{ 10 } \)

    (b)

    \(\frac { 3 }{ 10 } \)

    (c)

    \(\frac { 3 }{ 8 } \)

    (d)

    \(\frac { 6 }{ 7 } \)

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