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11th Standard English Medium Maths Subject Introduction To Probability Theory Creative 1 Mark Questions with Solution Part - II

11th Standard

    Reg.No. :
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Maths

Time : 01:00:00 Hrs
Total Marks : 5

    1 Marks

    5 x 1 = 5
  1. If P(A\(\cup \)B) = 0.8 and P(A\(\cap \)B) = 0.3 then \(P(\bar { A } )+P(\bar { B } )\) =

    (a)

    0.3

    (b)

    0.5

    (c)

    0.7

    (d)

    0.9

  2. If A and B are two events such that P(A) = \(\frac { 4 }{ 5 } \) and \(P(A\cap B)=\frac { 7 }{ 10 } \) then P(B/A) = 

    (a)

    \(\frac { 1 }{ 10 } \)

    (b)

    \(\frac { 1 }{ 8 } \)

    (c)

    \(\frac { 7 }{ 8 } \)

    (d)

    \(\frac { 17 }{ 20 } \)

  3. If P(B)=\(\frac { 3 }{ 5 } \)P(A/B) = \(\frac { 1 }{ 2 } \) and \(P(A\cup B)=\frac { 4 }{ 5 } \), then P(A) is

    (a)

    \(\frac { 3 }{ 10 } \)

    (b)

    \(\frac { 1 }{ 2 } \)

    (c)

    \(\frac { 1 }{ 10 } \)

    (d)

    \(\frac { 3 }{ 5 } \)

  4. If A and B are two independent events with P(A) = \(\frac { 3 }{ 5 } \) and P(B)=\(\frac { 4 }{ 9 } \) then \(P(\bar { A } \cap \bar { B } )\) = equals

    (a)

    \(\frac { 4 }{ 15 } \)

    (b)

    \(\frac { 8 }{ 45 } \)

    (c)

    \(\frac { 1 }{ 3 } \)

    (d)

    \(\frac { 2 }{ 9 } \)

  5. Choose the incorrect pair:

    (a)

    A and B disjoint - P(A⋂B) = peA) + PCB

    (b)

    A and B independent - P(A⋂B) = p(A) P(B)

    (c)

    A and B disjoint - P(A⋂B) = 0

    (d)

    A and B independent - P(A/B) = P(B/A)

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