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12th Standard English Medium Chemistry Subject Carbonyl Compounds Creative 3 Mark Questions with Solution Part - II

12th Standard

    Reg.No. :
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Chemistry

Time : 00:30:00 Hrs
Total Marks : 15
    5 x 3 = 15
  1. How will you convert benzaldehyde to
    (I) C6H5COOH
    (ii) C6HsCH2OH
    (iii) C6HSCH3

  2. What is Malachite green dye? Explain its preparation?

  3. Formic acid reduces Tollen's reagent but acetic acid does not - Give reasons.

  4. Write the structure of 'A' and 'B' in the following reaction
    \({ C }_{ 6 }{ H }_{ 5 }MgBr+{ CO }_{ 2 }\overset { (i)CO_{ 2 } }{ \underset { (ii){ H }_{ 2 }O/{ H }^{ + } }{ \longrightarrow } } A\overset { { Br }_{ 2 } }{ \underset { FeBr_{ 3 } }{ \longrightarrow } } B\)

  5. Give the IUPAC names for the following:
    (i) Crotonaldehyde
    (ii) Methyl n-propyl ketone
    (iii) Phenyl acetaldehyde.

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