10th Standard Syllabus & Materials
10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Population, Transport, Communication and Trade Important Questions And Answers Study Material - QB365 Set C
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Population, Transport, Communication and Trade Important Questions And Answers Study Material - QB365 Set B
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Population, Transport, Communication and Trade Important Questions And Answers Study Material - QB365 Set A
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Resources and Industries Important Questions And Answers Study Material - QB365 Set C
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Resources and Industries Important Questions And Answers Study Material - QB365 Set B
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Resources and Industries Important Questions And Answers Study Material - QB365 Set A
Published on: 13/05/2022
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Questions + Answers key
Take MCQ Maths Test1.
In an A.P., the first term is 1 and the common difference is 4. How many terms of the A.P. must be taken for their sum to be equal to 120?
6
7
8
9
2.
If A = 265 and B = 264 + 263 + 262 +...+ 20 Which of the following is true?
B is 264 more than A
A and B are equal
B is larger than A by 1
A is larger than B by 1
3.
The next term of the sequence \(\frac { 3 }{ 16 } ,\frac { 1 }{ 8 } ,\frac { 1 }{ 12 } ,\frac { 1 }{ 18 } \), ..... is
\(\frac { 1 }{ 24 } \)
\(\frac { 1 }{ 27 } \)
\(\frac { 2 }{ 3 } \)
\(\frac { 1 }{ 81 } \)
4.
If the sequence t1, t2, t3... are in A.P. then the sequence t6, t12, t18,.... is
a Geometric Progression
an Arithmetic Progression
neither an Arithmetic Progression nor a Geometric Progression
a constant sequence
5.
The value of (13 + 23 + 33 +...+153) - (1 + 2 + 3 +...+ 15)is
14400
14200
14280
14520
1.
(c)
8
2.
(i) To check if h is one – one, we assume that h(b1) = h(b2)
Then we get 2.47b1 + 54.10 = 2.47 b2 + 54.10
2.47b1 = 2.47b2 ⇒ b1 = b2
Thus, h(b1) = h(b2) ⇒ b1 = b2, So, the function h is one – one.
(ii) If the length of the thigh bone b = 50, then the height is
h(50) = (2.47 x 50) + 54.10 = 177.6 cms
(iii) If the height of a person is 147.96 cms, then h(b) =147.96 and so the length of the thigh bone is given by 2.47b + 54.10 = 147.96.
b = \(\frac { 93.86 }{ 2.47 } \)
Therefore, the length of the thigh bone is 38 cms.
3.
(b)
\(\frac { 1 }{ 27 } \)
4.
(b)
an Arithmetic Progression
5.
(c)
14280
10th Standard Syllabus & Materials
10th Standard
Tamilnadu 10th Standard Social Science GEO - Climate and Natural Vegetation of India Important Questions And Answers Study Material - QB365 Set C
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - Climate and Natural Vegetation of India Important Questions And Answers Study Material - QB365 Set B
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - Climate and Natural Vegetation of India Important Questions And Answers Study Material - QB365 Set A
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Location, Relief and Drainage Important Questions And Answers Study Material - QB365 Set B
Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards
