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TN 11th Tamil இயற்கை வேளாண்மை,சுற்றுச்சூழல் -செய்யுள் - மனோன்மணீயம் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - இலக்கணம் - பகுபத உறுப்புகள் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - துணைப்பாடம் - வாடிவாசல் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A
Published on: 13/05/2022
QB365 provides detailed and simple solution for every
Creative Questions in class 11 Chemistry Subject. It will
helps to get more idea about question pattern in every Creative questions with solution.
Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test1.
Calculate the oxidation number of underlined atoms \(H_{ 4 }\underline { { P }_{ 2 } } { O }_{ 7 }\)
2.
Calculate the molecular mass of the following Methane
3.
Calculate the molecular mass of the following Crystalline oxalic acid
4.
Calculate the molecular mass of the following KMnO4
5.
Elucidate the steps involved in arriving at the molecular formula of a compound.
1.
4(1) + 2x + 7(-2) = 0
4 + 2x - 14 = 0
2x - 10 = 0
2x = 10
x = 5
Oxidation number of P in H4P2O7 is +5.
2.
C ⟶ 1 \(\times\)12 =12
H ⟶ 4\(\times\) 1 = 4
\(\underline { \overline { 16 } } \)
∴ Molecular mass of CH4 = 16
3.
\(\overset { COOH }{ \underset { COOH }{ |\quad \quad \quad } } .2{ H }_{ 2 }O\)
C ⟶ 1 \(\times\) 12 = 24
O ⟶ 4 \(\times\) 16 = 64
H2 \(\times\) 1 = 2
\(\underline { \overline { 90 } } \)
4\(\times\) 1 = 4
2 \(\times\)16 = 32
\(\underline { \overline { 126 } } \)
∴ Molecular mass of oxalic acid 126
4.
1 atomic mass of K = 1 \(\times\) 39 = 39
Mn = 1\(\times\) 55 = 55
O = 4\(\times\) 16 = 63
\(\overline { \underline { 158 } } \)
∴ Molecular mass of KMnO4 = 158
5.
Step 1: Moles of the element = \(\frac { percentage\ of\ element }{ at.mass } \)
Step 2: Simplest molar ratio = \(\frac { molar\ ratio }{ minium\ molar\ ratio } \)
Step 3: Empirical Formula
Step 4; \(\frac { Molar\ mass }{ Empirical\ formula\ mass } \) = n
Molecular formula = n x Empirical formula n is integer such as 1, 2, 3...etc
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - உரைநடை - மலை இடப்பெயர்கள் : ஓர் ஆய்வு Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - துணைப்பாடம் - யானை டாக்டர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set A
Tamilnadu Stateboard 11th Standard Subjects
Maths
Commerce
Economics
Biology
Business Maths and Statistics
Accountancy
Computer Science
Physics
Chemistry
Maths
Biology
Economics
Physics
Chemistry
History
Business Maths and Statistics
Computer Science
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Computer Applications
History
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