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Published on: 25/10/2025
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Questions + Answers key
Take MCQ Chemistry Test

2 Marks
1.
How will you bring about the following conversions?
(i) Nitrobenzene to Phenol.
(ii) Aniline to Chlorobenzene.
2.
How will you bring about the following conversions?
(i) Ethanamine to Ethanoic acid
(ii) Aniline to Benzonitrile
3.
Complete the following reaction equations:
\((i)\ C_6H_5NH_2+CHCl_3+KOH(alc)\rightarrow\)
(ii) \(C_6H_5N_2Cl+H_3PO_2+H_2O\rightarrow\)
4.
Why cannot aromatic primary amines be prepared by Gabriel phythalimid synthesis?
5.
Out of ethylamine and ethyl alcohol which has higher boiling boiling point and why?
6.
Write IUPAC names of the following compounds and classify them into primary, secondary and teetiary amines.
(i) (CH3)2CHNH2
(ii) CH3(CH2)2NH2
(iii) CH3NHCH(CH3)2
(iv)(CH3)3CNH2
7.
How will you convert:
(i) Nitromethane into dimethylamine,
(ii) Propanoic acid into ethanoic acid?
8.
What is the rol of HNO3 in the nitrating mixture used for nitration of benzene?
9.
What is Hinsberg reagent?
10.
Why is benzenediazonium chloride not stored and is used immediately after its preparation?
11.
Name reagents required for preparation of methyl orange indicator (no reaction).
12.
What is Baker Mulliken's test? Discuss its chemistry.
13.
Give chemical tests to distinguish between the following pairs of compounds:
(i) Aniline and Ethylamine
(ii) Ethylamine and Dimethylamine
14.
What happens when
(i) toluene is treated with conc. HNO3 and conc. H2SO4 at 293 K?
(ii) nitrobenzene is treated with conc. HNO3 and conc. H2SO4 at 363 K?
15.
(a) Write a chemical test to distinguish between dimethyl amine and ethanamine.
(b) Write the product formed when benzene diazonium chloride is treated with KI.
3 Marks
16.
How are the following conversions carried out?
(i) Aniline to nitrobenzene
(ii) Ethanamine to N-ethylethanamid
(iii) Chloroethane to propan-1-amine
17.
Give one chemical test each to distinguish between the compounds in the following pairs:
(i) Methyleamine and dimethylamine
(ii) Aniline and benzylamine
(iii) Ethylamine and aniline
18.
How would you achieve the following conversions?
(i) Nitrobenzene to aniline
(ii) An alkyl halide to a quaternary ammonium salt.
(iii) Aniline to benzonitrile.
Write the chemical equation with reaction conditions in each case.
19.
(i) Give the structures of different isomeric amines corresponding to the molecular formula, C4H11N.
(ii) Write the IUPAC names of all the isomers.
(iii) What type of isomerism is exhibited by different pairs of amines?
20.
Write chemical equations for the following reactions:
(i) Reaction of ethanolic NH3 with C2H5Cl
(ii) Ammonolysis of Benzyl chloride and reaction of amine so formed with two moles of CH3Cl.
21.
Accmplish the following conversions:
(i) Aniline to 2,4,6-tribromofluorobenzene
(ii) Benzyl chloride to 2-phenylethanamine
(iii) Chlorobenzene to p-chloroaniline.
22.
Accomplish the following conversions:
(i) Aniline to p-bromoaniline
(ii) Benzamide to toluene
(iii) Aniline to benzyle alcohol
23.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3)2CHNH2
(ii) CH3(CH2)2NH2
(iii) CH3NHCH(CH3)2
(iv) (CH3)3CNH2
(v) C6H5NHCH3
(vi) (CH2CH2)2NCH3
(vii) m-BrC6H4 NH2.
24.
Why does bromination of aniline, even under very mild conditions, gives 2, 4, 6-tribromoaniline instantaneously?
25.
Write the structures of A, Band C in the following:
(i) C6H5-CONH2
(i) \({ CH }_{ 3 }-CI\overset { KCN }{ \longrightarrow } A\overset { { LiAIH }_{ 4 } }{ \longrightarrow } b\overset { { CHCI }_{ 3 }+alc.KOH }{ \longrightarrow } C.\)
2 Marks
1.

2.

3.
(i) \(\underset { Aniline }{ C_{ 6 }H_{ 5 }NH_{ 2 } } +CHCl_{ 3 }+\underset { (alc) }{ 3KOH } \quad { \longrightarrow }\underset { Phenyl\quad carbylamine }{ C_{ 6 }H_{ { 5 } }N_{ \rightarrow }^{ = }C } +3KCl+3H_{ 2 }O\)
(ii) \(\underset { Benzene\\ diazonium\\ Chloride }{ C_{ 6 }H_{ 5 }N_{ 2 }Cl } +\underset { Hypo\\ phosphorus\quad \\ acid }{ H_{ 3 }PO_{ 2 } } +H_{ 2 }O\quad { \longrightarrow }\underset { Benzene }{ C_{ 6 }H_{ 6 } } +\underset { Phosphoric\\ acid }{ H_{ 3 }PO_{ 3 } } +N_{ 2 }+HCl\)
4.
It is because there is double bond character between C\(\rightarrow\)X bond due to which it cannot be broken easily that is why aromatic amines cannot be prepared by Gabriel phthalimide synthesis.
5.
Ethyl alcohol has higher boiling point than ethlamine because there is stronger intermolecular H- bonding in ethanol than ethylamine due to more electronegativity of oxygen than nitrogen.
6.
(i) 2-Propanamine \(\left( { 1 }^{ \circ } \right) \)
(ii) 1-Propanamine \(\left( { 1 }^{ \circ } \right) \)
(iii) N-Methyl-2-propanamine \(\left( { 2 }^{ \circ } \right) \)
(iv) 2-Methyl-2-propanamine \(\left( { 1 }^{ \circ } \right) \)
7.

8.
HNO acts as a base in the nitrating mixture (conc.HNO3+conc.H2SO4). H2SO4 acts on HNO3 to generate the electrophile, \({ NO }_{ 2 }^{ + }\) (nitronium ion)
9.
Benzenesulphonyl chloride (C6H5SO2CI) is called Hinsberg's reagent.
10.
Benzenediazonium chloride is unstable. Therefore, it cannot be stored. Instead it is used immediately after its preparation.
11.
Reagents required are:
(i) sulphanilic acid
(ii) N, N-dimethylaniline
(iii) NaNO2 HCI and
(iv) a base.
12.
Both aliphatic and aromatic nitro compounds on reduction in neutral medium, i.e., Zn dust and NH4Cl solution, give the corresponding hydroxylamines.
\({ C }_{ 6 }{ H }_{ 5 }{ NO }_{ 2 }\quad \quad \overset { Zn/{ NH }_{ 4 }Cl,{ H }_{ 2 }O }{ \underset { \Delta }{ \longrightarrow } } \quad \quad { C }_{ 6 }{ H }_{ 5 }NHOH\\ Nitrobenzene\quad \quad \quad \quad \quad phenylhydroxylamine\\ \)
These hydroxylamines, when warmed with Tollens' reagent, are easily oxidized to the corresponding nitroso compounds and thus reduce Tollens' reagent to metallic silver
\({ C }_{ 6 }{ H }_{ 5 }NHOH+2{ \left[ Ag{ \left( { NH }_{ 3 } \right) }_{ 2 } \right] }^{ + }+2{ OH }^{ - }\longrightarrow { C }_{ 6 }{ H }_{ 5 }N=O+2Ag\downarrow +4{ NH }_{ 3 }+2{ H }_{ 2 }O\)
This reaction is called Baker Mulliken's test and is used as a test for detection of nitro group in organic compounds.
13.
(i) Aniline forms diazonium salt with NaNO2/HCl which gives orange red dye with \(\beta\) -napththol. Ethyl amine does not give this test

(b) Ethyl amine gives foul smelling ethyl isocyanide on heating with chloroform and potassium hydroxide solution. Dimethyl amine does not give this test.
C2H5NH2+CHCI3+3KOH⟶C2H5NC+3KCI+3H2O
14.
15.
(a) Test for dimethyl amine and ethanamine Ethanamine, being primary amine, on heating with chloroform and ethanolic potassium hydroxide form isocyanide which have foul smell whereas dimethyl does not give this kind of foul smell.
| \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2+\mathrm{CHCl}_3+3 \mathrm{KOH} \xrightarrow{\Delta}\) | \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NC}+3 \mathrm{KCl}+3 \mathrm{H}_2 \mathrm{O}\) | \(\left(\mathrm{CH}_3\right)_2 \mathrm{NH}+\mathrm{CHCl}_3+3 \mathrm{KOH} \xrightarrow{\Delta} \text { No foul smell }\) |
| Ethanamine | Ethyl isocyanide | Dimethylamine |
(b) Benzene diazonium chloride when treated with KI form iodobenzene. The reaction involved is as follows

3 Marks
16.

17.
(i) Methylamine and dimethylamine can be distinguished by the carbylamine test. Carbylamine test: Aliphatic and aromatic primary amines on heating with chloroform and ethanolic potassium hydroxide form foul-smelling isocyanides or carbylamines. Methylamine (being aliphatic primary amine) gives a positive carbylamine test, but dimethylamine does not.
(ii) Secondary and tertiary amines can be distinguished by allowing them to react with Hinsbergs reagent (benzenesulphonyl chloride, C6H5SO2Cl). Secondary amines react with Hinsberg’s reagent to form a product that is insoluble in an alkali. For example, N, N−diethylamine reacts with Hinsberg’s reagent to form N, N−diethylbenzenesulphonamide, which is insoluble in an alkali. Tertiary amines, however, do not react with Hinsberg’s reagent amines, however, do not react with Hinsberg’s reagent.
(iii) Aniline and benzylamine can be distinguished by their reactions with the help of nitrous acid, which is prepared in situ from a mineral acid and sodium nitrite. Benzylamine reacts with nitrous acid to form unstable diazonium salt, which in turn gives alcohol with the evolution of nitrogen gas.
18.

19.
(i) and (ii)
Eight isomers of C4H11N are
(a) \(\stackrel{4}{\mathrm{C}} \mathrm{H}_3-\stackrel{3}{\mathrm{C}} \mathrm{H}_2-\stackrel{2}{\mathrm{C}} \mathrm{H}_2-\stackrel{1}{\mathrm{C}} \mathrm{H}_2-\mathrm{NH}_2\)
Butan -1 -amine
(Primary)
(b) CH3
|
\(\stackrel{3}{CH}_3-{ }^2 \mathrm{CH}-\stackrel{1}{C} \mathrm{H}_2-\mathrm{NH}_2\)
2-methyl propan -1-amine
(Primary)

(iii) Isomerism exhibited by different amines are:
(a) Chain isomers, i.e. have different carbon chains, (a) and (b), (c) and (d) (as discussed in part (i) and (ii)]
(b) Position isomers, i.e. functional group occupy different positions, (a) and (c), (b) and (d).
(c) Metamers, i.e. different alkyl groups are attached to the same functional group, (e) and (f), (e) and (g).
(d) Functional isomers, i.e. they have different functional groups. All the three categories (1°, 2° and 3°) of amines are the functional isomers of each other.
20.

21.
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22.

23.
(i) Propan-2-amine \(\left( { 1 }^{ \circ } \right) \),
(ii) Propan-1-amine \(\left( { 1 }^{ \circ } \right) \),
(iii) N-Methylpropan-2-amine \(\left( { 2 }^{ \circ } \right) \),
(iv) 2-Methylpropan-2-amine \(\left( { 3 }^{ \circ } \right) \),
(v) N-Methylbenzenamine or N-Methylaniline \(\left( { 2 }^{ \circ } \right) \),
(vi) N-Ethyl N-methylethanamine \(\left( { 3 }^{ \circ } \right) \),
(vii) 3-Bromobenzenamine or 3-Bromoaniline \(\left( { 1 }^{ \circ } \right) \).
24.
Due to strong electron-donating effect of the -NH2 group, the electron density increases at the 0-, positions. Further, when aniline is treated with Br2 the Br+ attacks the benzene ring at o- and p-positions to form carbocation intermediates which are stabilized not only by the usual resonance of the Henzene ring. but also by the -NH2 group as shown below: In case of o-bromination, the carbocation intermediate is stabilized not only by usual resonating structure (I, III and IV) but is also stabilized by resonance structure (II) in which the lone pair of electrons on the N. atom interacts with the positively charged carbon of the ring. Similarly, in case of p-bromination, the carbocation is stabilized not only by the usual resonating structures (V, VI, and VIII) but is also stabilized by the resonance structure (VII) in which the lone pair of electrons on the N-atom interacts with the positively charged carbon of the ring. These additional resonating structures (II and VII) increase the stability of the carbocation to such an extent that bromination occurs instantaneously at the p- and two. o- positions giving 2, 4, 6-tribromoaniline.
25.
(i) \({ C }_{ 6 }{ H }_{ 5 }-{ CONH }_{ 2 }\overset { { Br }_{ 2 }/KOH }{ \longrightarrow } { C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }\)
\([A]\overset { { NaNO }_{ 2 }+HCI }{ \longrightarrow } { C }_{ 6 }{ H }_{ 5 }{ N }_{ 2 }^{ + }{ CI }^{ - }[B]\overset { KI }{ \longrightarrow } { C }_{ 6 }{ H }_{ 5 }I[C]\)
(ii) \({ CH }_{ 3 }CI\overset { KCN }{ \longrightarrow } { CH }_{ 3 }CN[A]\overset { { LiAIH }_{ 4 } }{ \longrightarrow } { CH }_{ 3 }{ CH }_{ 2 }{ NH }_{ 2 }[B]\overset { { CHCI }_{ 3 }+KOH }{ \longrightarrow } { CH }_{ 3 }{ CH }_{ 2 }NC[C]\)
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