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cbse 12th Standard Chemistry Amines Model Questions Papers Study Material - QB365 Set B

Published on: 25/10/2025

Question Set B

cbse 12th Standard Chemistry Amines Model Questions Papers Study Material - QB365

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Std: 12th Standard CBSE - Chemistry

chapter: Amines - Model Questions Papers

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Questions:

Generic 2

30 x 2 = 60

Give plausible explanation for each of the following:
(i) Why are amines less acidic than alcohols of comparable molecular masses?
(ii) Why do primary amines have higher boiling points than tertiary amines?
(iii) Why are aliphatic amines stronger bases than aromatic amines?

Write the reactions of
(i) aromatic and
(ii) aliphatic primary amines with nitrous acid.

Convert
(i) 3-Methylaniline into 3-nitrotoluence
(ii) Aniline into 1, 3, 5-tribromobenzene.

Write chemical reaction of aniline with benzoyl chloride and write the name of the product abtained.

Write structures and IUPAC names of
(i) the amide which gives propanamide by Hoffmann bromamide reaction.
(ii) the amine produced by the Hofmann degradation of benzamide.

How will you carry out the following conversions?

How will you bring out the following conversion?

Write following conversions:
(i) nitrobenzene\(\longrightarrow \)acetanilide
(ii) acetanilide\(\longrightarrow \)p-nitroaniline

How will you carry out the following conversions?
(i) toluene \(\longrightarrow \) p-toluidine
(ii) p-toluidine diazonium chloride \(\longrightarrow \) p-toluic acid

10.

How will you convert 4-nitrotoluene to 2-bromobenzoic acid?

11.

Complete the following acid-base reactions and name the products:
(a) CH₃-CH₂-CH₂-NH₂+ HCI \(\rightarrow \)
(b) (C₂H₅)₃N+HCI \(\rightarrow \)

12.

Arrange the following in decreasing order of their basic strength:
C₆H₅NH₂, C₂H₅NH₂, (C₂H₅)₂ NH, NH₃

13.

Write chemical equations for the following conversions:
(i) CH₃-CH₂-Cl into CH₃-CH₂-CH₂-NH₂
(ii) C₆H₅-CH₂-Cl into C₆H₅-CH₂-CH₂-NH₂

14.

Classify the following amines as primary, secondary or tertiary:
(i)

(ii)

(iii) \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{CHNH}_{2}\)
(iv) \(\left[\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}\)

15.

Amino group is o, p-directing for aromatic electrophilic substitution. Why does aniline on nitroaniline?

16.

Out of ethylamine and ethyl alcohol which has higher boiling boiling point and why?

17.

How will you distinguish between C₆H₅CH₂NH₂ and C₆H₅NH₂? Write the chemical equations for the reactions involved.

18.

Arrange the following substances:
C₆H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N, C₂H₅NH₂
(i) In an increasing order of basic strength in water
(ii) In a decreasing order of basic strength in gas phase.

19.

Why cannot aromatic primary amines be prepared by Gabriel phythalimid synthesis?

20.

Complete the following reaction equations:
\((i)\ C_6H_5NH_2+CHCl_3+KOH(alc)\rightarrow\)
(ii) \(C_6H_5N_2Cl+H_3PO_2+H_2O\rightarrow\)

21.

Identify A and B in each of the following process:

22.

How will you bring the following conversions?
(i) Methanamine into Iodomethane
(ii) Chlorobenzene into p-chloroaniline.

23.

How will you bring about the following conversions?
(i) Ethanamine to Ethanoic acid
(ii) Aniline to Benzonitrile

24.

How will you bring about the following conversions?
(i) Nitrobenzene to Phenol.
(ii) Aniline to Chlorobenzene.

25.

Account for the following:
(i) Diazonium salts of aromatic amines are more stable than those of aliphatic amines.
(ii) Amines are more basic than alcoholes of comparable molecular masses.

26.

How can you convert aniline to iodobenzene?

27.

Give the structure of 'A' in the following reaction.

28.

Why are aqueous solutions of amines basic in nature?

29.

Why do amines react as nucleophiles?

30.

Why is an alkylamine more basic than ammonia?

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Answers Key:

Generic 2

30 x 2 = 60

(i) It is because C₂H₅O^- is more stable than C₂H₅NH^- because oxygen is more electronegative than nitrogen.
(ii) It is because primary amines are associated with intermolecular H-bonding, whereas tertiary arnines are not.
(iii) It is because there is electron withdrawing C₆H₅- group in aromatic amines which makes them less basic than aliphatic amines in which alkyl group is electron releasing.

(ii) \( { C }_{ 2 }{ H }_{ 5 }{ NH }_{ 2 }+{ \ HNO }_{ 2 } \longrightarrow { C }_{ 2 }{ H }_{ 5 }OH+{ N }_{ 2 }+{ H }_{ 2 }O\\ Ethanamine\quad \quad\quad\quad\quad Nitrus\quad acid\quad \quad \quad \quad Ethanol\)

(i) Propanamine contains three carbons. Hence, the amide molecule must contain four carbon atoms. Structure and IUPAC name of the starting amide with four carbon atoms are given below:

(ii) Benzamide is an aromatic amide containing seven carbon atoms. Hence, the amine formed from benzamide is aromatic primary amine containing six carbon atoms.

(ii) Follow procedures as in (i) till second last step

10.

11.

12.

The decreasing order of basic strength of the given amines and ammonia follows the following order:
(C₂H₅)NH > C₂H₅NH₂ > NH₃ > C₆H₅NH₂

13.

14.

(i) Primary
(ii) Tertiary
(iii) Primary
(iv) Secondary

15.

It is due to protonation of aniline to form C₆H₅NH₃which is electron with drawing, hence m-directing.

16.

Ethyl alcohol has higher boiling point than ethlamine because there is stronger intermolecular H- bonding in ethanol than ethylamine due to more electronegativity of oxygen than nitrogen.

17.

Add CHCI₃ and alc. KOH,C₆H₅- NH₂ gives foul smell of isocyanide whereas C₆H₅ - NH - CH₃ does not.

18.

19.

It is because there is double bond character between C\(\rightarrow\)X bond due to which it cannot be broken easily that is why aromatic amines cannot be prepared by Gabriel phthalimide synthesis.

20.

(i) \(\underset { Aniline }{ C_{ 6 }H_{ 5 }NH_{ 2 } } +CHCl_{ 3 }+\underset { (alc) }{ 3KOH } \quad { \longrightarrow }\underset { Phenyl\quad carbylamine }{ C_{ 6 }H_{ { 5 } }N_{ \rightarrow }^{ = }C } +3KCl+3H_{ 2 }O\)
(ii) \(\underset { Benzene\\ diazonium\\ Chloride }{ C_{ 6 }H_{ 5 }N_{ 2 }Cl } +\underset { Hypo\\ phosphorus\quad \\ acid }{ H_{ 3 }PO_{ 2 } } +H_{ 2 }O\quad { \longrightarrow }\underset { Benzene }{ C_{ 6 }H_{ 6 } } +\underset { Phosphoric\\ acid }{ H_{ 3 }PO_{ 3 } } +N_{ 2 }+HCl\)

21.

22.

23.

24.

25.

(i) It is because if resonance stabilization in diazonium salts of aromatic amines which is not possible in diazonium salts of aliphatic amines.
(ii) It is because 'N' is less electronegative than O, therefore, lone pair are easily avaiable.

26.

27.

28.

\(\mathrm{RNH}_2+\mathrm{H}_2 \mathrm{O} \longrightarrow \stackrel{\oplus}{\mathrm{N}} \mathrm{H}_3+\mathrm{OH}^{-}\). It is due to formation of OH^-.

29.

It is due tp presence of lone pair of electronson nitrogen which they can donate and act as nucleophiles.

30.

It is because alkyl groups are electron releasing in alkyl amines, they will increase electron density on 'N', therefore, they are more basic than NH₃.