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Published on: 25/10/2025
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1.
Benzene diazonium chloride on hydrolysis gives.
Phenol
Chlorobenzene
Benzene
Aniline
2.
Which of the following should be most volatile?
(I) CH3CH2CH2NH2
(II) (CH3)3N

(IV) CH3CH2CH3
II
IV
I
III
3.
Among the following amines, the strongest Bronsted base is _____________

NH3


4.
Acid anhydrides on reaction with primary amines give ____________
amide
imide
secondary amine
imine
5.
The most reactive amine towards dilute hydrochloric acid is ___________
CH3 - NH2



6.
The product of the following reaction is ___________





7.
4-Nitrotoluene is treated with bromine to get P. 'P' is reduced with Sn/HCI to get compound 'Q'. 'Q' is diazotised and the product is treated with phosphinic acid to get compound 'R'. 'R' is oxidised with alkaline KMnO4 to get 'S'. Compound'S' is
2-Bromo-4-hydroxy benzoic acid
2-Bromo benzoic acid
3-Bromo benzoic acid
4-Bromo benzoic acid
8.
\(^{\prime} \mathrm{A}^{\prime}\stackrel{\text { Reduction }}{\longrightarrow}{ }^{\prime} \mathrm{B}^{\prime} \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
The compound' A' is
propane nitrile
ethane nitrile
nitro methane
methyl isocyanate
9.
The reaction of P:Toluidine with CHCl3 and KOH gives




10.

\(\beta\)-Alanine
\(\alpha\)-Alanine
Ethylene diamine
Oxamide
11.
In the reaction C6H5CONH2 \(\xrightarrow[{\triangle }]{Br_2+KOH}\)Major product A is
C6H6
C6H5CHO
C6H5NH2
C6H5COOKI
12.
The correct name for yellow dye is
p-hydroxy azobenzene
p-amino azobenzene
o-hydroxyazobenzene
o-amino azobenzene
13.
Which of the following compound will not undergo azo coupling reaction with benzene diazonium chloride?
Aniline
Phenol
Anisole
Nitrobenzene
14.
Benzene diazonium chloride when reacts with hypophosphorus acid produces
Benzene
Phenol
Phenol isocyanide
Phenyl phosphate
15.
Which of the following products is formed in the given reaction?
16.
Which of the following reactions is/are electrophilic substitution?
Bromination of aniline
Nitration of aniline
Sulphonation of aniline
All of the above
17.
Name the product(s) formed during the reaction of primary aliphatic amines with nitrous acid at room temperature?
\(\begin{equation} R \mathrm{~N}_{2}^{+} \mathrm{Cl^-} \end{equation}\)
ROH
Both (a) and (b)
None of the above
18.
Which of the following products is formed in the given reaction?
RNH2
RCH2NH2
RCH2CH2NH2
19.
p-Chloroaniline and anilinium hydrochloride can be distinguished by
Sandmeyer reaction
NaHCO3 solution
AgNO3 solution
Carbylamine reaction
20.
A positive carbylamine test is given by
N, N-dimethylaniline
2, 4-dimethylaniline
N-methyl-o-methylaniline
p-methylbenzylamine
21.
Reduction of benzenediazonium chloride with Zn/HCI hives
aniline
phenylhydrazine
azobenzene
hydrazobenzene
22.
Which of the following will be the most stable diazonium salt, \({ RN }_{ 2 }^{ + }{ X }^{ - }\) ?
\(CH_{ 3 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
\({ C }_{ 6 }H_{ 5 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
\(CH_{ 3 }{ CH }_{ 2 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
\({ C }_{ 6 }H_{ 5 }{ CH }_{ 2 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
23.
Which of the following diazonium salt is most stable?
p-Nitrobenzenediazonium chloride
2, 4-Dinitrobenzenediazonium chloride
2, 4, 6-Trinitrobenzenediazonium chloride
p-Methoxybenzenediazonium chloride
24.
During the preparation of arenediazonium salts, the excess of nitrous acid, if any, is destroyed by adding.
Aq.NaOH
Aq.Na2CO3
Aq.NH2CONH2
Aq.KI
25.
What reagent is used in Hinsberge test of amines?
(CH3CO)2O and pyridine
C6H5SO2CI in aq.NaOH
NaNO2 in aq.H2SO4
CH3I (excess) followed by AgOH
26.
\({ C }_{ 6 }{ H }_{ 5 }COOH \ \overset { 1.{ NH }_{ 3 } }{ \underset { 2.\triangle }{ \longrightarrow } } P\overset { NaOBr }{ \longrightarrow } Q\quad \overset { 1. \ Conc.{ H }_{ 2 }{ SO }_{ 4 } }{ \underset { 2. \ heat\ \ to\ \ 460\ \ K }{ \longrightarrow } } \ \ \ \ R\) 'R' is
o-bromosulphanilic acid
sulphanilamide
sulphanilic acid
p-bromosulphanilamide
27.
Anilinium hydrogen sulphate on heating with sulphuric acid at 453-473 produces
benzenesulphonic acid
anthranilic acid
anline
m-aminobenzenesulphonic acid
sulphanilic acid
28.
Amino group is ortho-, para-directing for aromatic electrophilic substitution. On nitration of aniline, good amount of m-nitroaniline is obtained. This is due to
In nitration mixture, ortho, para-activity of NH2 group is completely lost
-NH2 becomes \(-{ NH }_{ 3 }^{ + }\), which is m-directing
-NH2 becomes -NH+ \({ SO }_{ 4 }^{ - }\) , which is m-directing
-NH2 becomes -NH- \({ NO }_{ 2 }^{ + }\), which is m-directing
29.
Which gives black precipitate on reaction with CS2 followed by addition of HgCl2?
(CH3)3CNH2
(C2H5)2NH
(CH3)3N
all the three
30.
The compound which gives an oily nitrosoamine on reaction with nitrous acid at low temperature is
CH3NH2
(CH3)2CHNH2
CH3-NH-CH3
(CH3)3N
31.
Positive carbylamine test is shown by
N, N-dimethylaniline
triethylamine
N-methylaniline
p-methylbenzylamine
dimethylamine
32.
In the chemical reaction, CH3CH2NH2+CHCI3+3 KOH \(\longrightarrow \) (A) + (B) + 3 H2O. The compopund (A) and (B) are respectively.
C2H5NC and 3 KCI
C2H5CN and 3 KCI
CH3CH2CONH2 and 3 KCI
C2H5NC and K2CO3
33.
A compound with molecular mass 180 is acylated with CH3COCI to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is
6
2
5
4
34.
The strongest base in aqueous solution among the following amines is
N, N-diethylethanamine
N-ethylethanamine
N-methylmethanamine
ethanamine
phenylmethanamine
35.
Considering the basic strength of amines in aqueous solution, which one has the smallest pKb value?
C6H5NH2
(CH3)2NH
CH3NH2
(CH3)3N
36.
Amongst the following amines, which one has the highest pKb value in aqueous solution?
Methanamine
N, N-Dimethylaniline
Ethanamine
Benzenamine
N, N-Diethylethanamine
37.
Which of the following compounds is most basic?
Aniline
Cyclohexylamine
o-Nitroaniline
o-Toluidine
p-Methoxyaniline
38.
The correct order of basic strength of CH3NH2(I), (CH3)2NH(II), (CH3)3N(III), C6H5CH2NH2(IV) in gaseous phase is
IV < III < II < I
IV < III < I < II
I < II < III < IV
IV < I < II < III
39.
Mendius reduction converts an alkyl cyanide to
a primary amine
an aldehyde
a ketone
an oxime
40.
m-Bromoaniline can be prepared by
\({ C }_{ 6 }{ H }_{ 6 }\quad \overset { { HNO }_{ 3 } }{ \underset { { H }_{ 2 }{ SO }_{ 4 } }{ \longrightarrow } } \quad \overset { 1.Sn-HCI }{ \underset { { 2.NaOH,H }_{ 2 }O }{ \longrightarrow } } \quad \overset { { Br }_{ 2 } }{ \underset { H_{ 2 }O }{ \longrightarrow } } \)
\({ C }_{ 6 }{ H }_{ 6 }\ \overset { { Br }_{ 2 } }{ \underset { { FeBr }_{ 3 } }{ \longrightarrow } } \quad \overset { { HNO }_{ 3 } }{ \underset { H_{ 2 }{ SO }_{ 4 } }{ \longrightarrow } } \quad \overset { { H }_{ 2 } }{ \underset { Pt }{ \longrightarrow } } \)
\(m-Br{ C }_{ 6 }{ H }_{ 4 }COOH\ \overset{ SOCI_{ 2 } }{ \longrightarrow } \quad \overset { NH_{ 3 } }{ \longrightarrow } \quad \overset { Br_{ 2 },NaOH }{ \longrightarrow } \)
\({ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }\quad \overset { { NaNO }_{ 2 },HCI }{ \underset { { Cu }_{ 2 }Br_{ 2 } }{ \longrightarrow } } \overset { SOCI_{ 2 } }{ \longrightarrow } \quad \overset { NaNH_{ 2 } }{ \longrightarrow } \)
41.
Method by which aniline cannot be prepared is
degradation of benzamide with bromine in alkaline solution
reduction of nitrobenzene with H2/Pd in ethanol
potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution.
hydrolysis of phenylisocyanide with acidic solution
42.
Which of the following compounds will not undergo Friedel-Crafts reaction easily?
Nitrobenzene
Toluene
Cumene
Xylene
43.
The electrolytic reduction of nitrobenzene in strongly acidic medium produces.
azobenzene
aniline
p-aminophenol
azoxybenzene
44.
Nitrobenzene on reaction with conc.HNO3/H2SO4 at 80-\({ 100 }^{ \circ }\)C forms which one of the following products?
1, 4-Dinitrobenzene
1, 2, 4-Trinitrobenzene
1,2-Dinitrobenzene
1, 3-Dinitrobenzene
45.
Which of the following reagents would not be a good choice for reducing an aryl nitro compound to an amine?
H2 (excess) / Pt
LiAIH4 in ether
Fe and HCI
Sn and HCI
46.
Which of the following exists as a zwitterion?
p-Aminophenol
Salicylic acid
p-Aminophenol
Salicylic acid
47.
When ethylamine is treated with CH3MgBr, the product is:
CH3CH3
CH4
CH3CH2CH3
CH3CH2CH2CH3
48.
Ethylamine on heating with CS2 in presence of HgCl2 forms
\({ C }_{ 2 }{ H }_{ 5 }NCS\)
\(\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }S\)
\(\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }CS\)
\({ C }_{ 2 }{ H }_{ 5 }\left( CS \right) _{ 2 }\)
49.
When a primary amine reacts with chloroform and ethanolic KOH, then the product formed is
isocyanide
aldehyde
cyanide
alcohol
50.
Which of the following is most basic?
Benzylamine
Aniline
Acetanilide
p-Nitroaniline
1.
(a)
Phenol
2.
(b)
IV
3.
(d)

4.
(a)
amide
5.
(b)

6.
(a)

7.
(b)
2-Bromo benzoic acid
8.
(b)
ethane nitrile
9.
(d)

10.
(a)
\(\beta\)-Alanine
11.
(b)
C6H5CHO
12.
(b)
p-amino azobenzene
13.
(d)
Nitrobenzene
14.
(a)
Benzene
15.
(d)
16.
(d)
All of the above
17.
(b)
ROH
18.
(b)
RCH2NH2
19.
Both p-chloroaniline and anilinium hydrochloride are \({ 1 }^{ \circ }\) amines and hence cannot be ditinguished by carbylamine reaction.
20.
2, 4-Dimethylaniline and p-methylbenzylamine are \({ 1 }^{ \circ }\) amines and hence give positive carbylamine test.
21.
\({ C }_{ 6 }H_{ 5 }{ N }_{ 2 }CI\overset { Zn/HCI }{ \longrightarrow } { C }_{ 6 }H_{ 5 }{ NH }_{ 2 }+{ NH }_{ 3 }\)
22.
Due to delocalization of the +ve charge on the benzene ring, aromatic diazonium salts are more satble, i.e., option (b) is correct.
23.
Electron donating groups increase the stability of diazonium cations by dispersing the +ve charge on the N-atom.
24.
Urea decomposes \({ NH }_{ 2 }{ CONH }_{ 2 }\ +\ 2HONO\longrightarrow 2{ N }_{ 2 }\uparrow +{ CO }_{ 2 }\uparrow +3{ H }_{ 2 }O.\)
25.
(b)
C6H5SO2CI in aq.NaOH
26.
(c)
sulphanilic acid
27.
(e)
sulphanilic acid
28.
Protonation of the-NH2 group gives NH3 which is m-directing.
29.
Only \({ 1 }^{ \circ }\) amines undergo Hofmann Mustard oil reaction and thus give a black ppt. of HgS.
30.
\({ 2 }^{ \circ }\) Amines, i.e., (CH3)2NH, on treatment with HNO2 give oily nitrosamines.
31.
Only \({ 1 }^{ \circ }\) amines, i.e., p-methylbenzylamine, (p) CH3-C6H4-CH2NH2, give carbylamine test.
32.
(a)
C2H5NC and 3 KCI
33.
(c)
5
34.
Amines are stronger bases than amines followed by amines. Further, among amines, (C2H5)2NH is more basic than (CH3)2NH due to stronger +I-effect of the CH3CH2 over CH3 group. Thus, option (b) is correct.
35.
A strongest base has the smallest pKb, i.e. option (b) is correct.
36.
All aliphatic amines are more basic than benzenamine. Further, due to the presence of two CH3 groups on N in N, N-dimethylaniline, it is more basic than aniline or benzenamine. Hence, benzenamine is the weakest base base and hence has the highest pKb value.
37.
Aliphatic/alicyclic amines are more basic than aromatic amines. Therefore, cyclohexylamine is most basic.
38.
In the gaseous phase, basicity increases as the + I-effect of the alkyl groups increases, i.e., CH3NH2(I) < (CH3)2 NH < (CH3)3 N (III). However, due to -I-effect of the CH- group, CHCHNH (IV) is even a weaker base than CHNH (I). Thus, the overall, basic character increases in the order : IV < I < II < III.
39.
(a)
a primary amine
40.
(c)
\(m-Br{ C }_{ 6 }{ H }_{ 4 }COOH\ \overset{ SOCI_{ 2 } }{ \longrightarrow } \quad \overset { NH_{ 3 } }{ \longrightarrow } \quad \overset { Br_{ 2 },NaOH }{ \longrightarrow } \)
41.
Aniline cannot be prepared by Gabriel phthalimide method because chlorobenzene (i.e.,aryl halide) does not undergo nucleophilic substitution reaction with potassium phthalimide in aqueous NaOH solution.
42.
-NO2 is a powerful dectivating group. It reduces the electron density in the benzene ring considerably. As a result, it does not undergo F.C.reactions.
43.
Electrolytic reduction of nitrobenzene in strongly acidic medium gives p-aminophenol.
44.
-NO2 is a m-directing group and hance 1, 3-dinitrobenzene is formed.
45.
(b)
LiAIH4 in ether
46.
Sulphonilic acid exists as a zwitterion.
47.
(b)
CH4
48.
(a)
\({ C }_{ 2 }{ H }_{ 5 }NCS\)
49.
Carbylamine reaction yields isocyanides.
50.
Benzylamine is most basic
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