Question Set C

cbse 12th Standard Chemistry Amines Model Questions Papers Study Material - QB365

Download CBSE Class 12th Standard CBSE Chemistry question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 12th Standard CBSE Chemistry

Questions:

Multiple Choice Question

Which of the following is most basic?

(a)

Benzylamine

(b)

Aniline

(c)

Acetanilide

(d)

p-Nitroaniline

When a primary amine reacts with chloroform and ethanolic KOH, then the product formed is

(a)

isocyanide

(b)

aldehyde

(c)

cyanide

(d)

alcohol

Ethylamine on heating with CS₂ in presence of HgCl₂ forms

(a)

\({ C }_{ 2 }{ H }_{ 5 }NCS\)

(b)

\(\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }S\)

(c)

\(\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }CS\)

(d)

\({ C }_{ 2 }{ H }_{ 5 }\left( CS \right) _{ 2 }\)

When ethylamine is treated with CH₃MgBr, the product is:

(a)

CH₃CH₃

(b)

CH₄

(c)

CH₃CH₂CH₃

(d)

CH₃CH₂CH₂CH₃

Which of the following exists as a zwitterion?

(a)

p-Aminophenol

(b)

Salicylic acid

(c)

p-Aminophenol

(d)

Salicylic acid

Which of the following reagents would not be a good choice for reducing an aryl nitro compound to an amine?

(a)

H₂ (excess) / Pt

(b)

LiAIH₄ in ether

(c)

Fe and HCI

(d)

Sn and HCI

Nitrobenzene on reaction with conc.HNO₃/H₂SO₄ at 80-\({ 100 }^{ \circ }\)C forms which one of the following products?

(a)

1, 4-Dinitrobenzene

(b)

1, 2, 4-Trinitrobenzene

(c)

1,2-Dinitrobenzene

(d)

1, 3-Dinitrobenzene

The electrolytic reduction of nitrobenzene in strongly acidic medium produces.

(a)

azobenzene

(b)

aniline

(c)

p-aminophenol

(d)

azoxybenzene

Which of the following compounds will not undergo Friedel-Crafts reaction easily?

(a)

Nitrobenzene

(b)

Toluene

(c)

Cumene

(d)

Xylene

10.

Method by which aniline cannot be prepared is

(a)

degradation of benzamide with bromine in alkaline solution

(b)

reduction of nitrobenzene with H₂/Pd in ethanol

(c)

potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution.

(d)

hydrolysis of phenylisocyanide with acidic solution

11.

m-Bromoaniline can be prepared by

(a)

\({ C }_{ 6 }{ H }_{ 6 }\quad \overset { { HNO }_{ 3 } }{ \underset { { H }_{ 2 }{ SO }_{ 4 } }{ \longrightarrow } } \quad \overset { 1.Sn-HCI }{ \underset { { 2.NaOH,H }_{ 2 }O }{ \longrightarrow } } \quad \overset { { Br }_{ 2 } }{ \underset { H_{ 2 }O }{ \longrightarrow } } \)

(b)

\({ C }_{ 6 }{ H }_{ 6 }\ \overset { { Br }_{ 2 } }{ \underset { { FeBr }_{ 3 } }{ \longrightarrow } } \quad \overset { { HNO }_{ 3 } }{ \underset { H_{ 2 }{ SO }_{ 4 } }{ \longrightarrow } } \quad \overset { { H }_{ 2 } }{ \underset { Pt }{ \longrightarrow } } \)

(c)

\(m-Br{ C }_{ 6 }{ H }_{ 4 }COOH\ \overset{ SOCI_{ 2 } }{ \longrightarrow } \quad \overset { NH_{ 3 } }{ \longrightarrow } \quad \overset { Br_{ 2 },NaOH }{ \longrightarrow } \)

(d)

\({ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }\quad \overset { { NaNO }_{ 2 },HCI }{ \underset { { Cu }_{ 2 }Br_{ 2 } }{ \longrightarrow } } \overset { SOCI_{ 2 } }{ \longrightarrow } \quad \overset { NaNH_{ 2 } }{ \longrightarrow } \)

12.

Mendius reduction converts an alkyl cyanide to

(a)

a primary amine

(b)

an aldehyde

(c)

a ketone

(d)

an oxime

13.

The correct order of basic strength of CH₃NH₂(I), (CH₃)₂NH(II), (CH₃)₃N(III), C₆H₅CH₂NH₂(IV) in gaseous phase is

(a)

IV < III < II < I

(b)

IV < III < I < II

(c)

I < II < III < IV

(d)

IV < I < II < III

14.

Which of the following compounds is most basic?

(a)

Aniline

(b)

Cyclohexylamine

(c)

o-Nitroaniline

(d)

o-Toluidine

(e)

p-Methoxyaniline

15.

Amongst the following amines, which one has the highest pK_b value in aqueous solution?

(a)

Methanamine

(b)

N, N-Dimethylaniline

(c)

Ethanamine

(d)

Benzenamine

(e)

N, N-Diethylethanamine

16.

Considering the basic strength of amines in aqueous solution, which one has the smallest pK_b value?

(a)

C₆H₅NH₂

(b)

(CH₃)₂NH

(c)

CH₃NH₂

(d)

(CH₃)₃N

17.

The strongest base in aqueous solution among the following amines is

(a)

N, N-diethylethanamine

(b)

N-ethylethanamine

(c)

N-methylmethanamine

(d)

ethanamine

(e)

phenylmethanamine

18.

A compound with molecular mass 180 is acylated with CH₃COCI to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

(a)

(b)

(c)

(d)

19.

In the chemical reaction, CH₃CH₂NH₂+CHCI₃+3 KOH \(\longrightarrow \) (A) + (B) + 3 H₂O. The compopund (A) and (B) are respectively.

(a)

C₂H₅NC and 3 KCI

(b)

C₂H₅CN and 3 KCI

(c)

CH₃CH₂CONH₂ and 3 KCI

(d)

C₂H₅NC and K₂CO₃

20.

Positive carbylamine test is shown by

(a)

N, N-dimethylaniline

(b)

triethylamine

(c)

N-methylaniline

(d)

p-methylbenzylamine

(e)

dimethylamine

21.

The compound which gives an oily nitrosoamine on reaction with nitrous acid at low temperature is

(a)

CH₃NH₂

(b)

(CH₃)₂CHNH₂

(c)

CH₃-NH-CH₃

(d)

(CH₃)₃N

22.

Which gives black precipitate on reaction with CS₂ followed by addition of HgCl₂?

(a)

(CH₃)₃CNH₂

(b)

(C₂H₅)₂NH

(c)

(CH₃)₃N

(d)

all the three

23.

Amino group is ortho-, para-directing for aromatic electrophilic substitution. On nitration of aniline, good amount of m-nitroaniline is obtained. This is due to

(a)

In nitration mixture, ortho, para-activity of NH₂ group is completely lost

(b)

-NH₂ becomes \(-{ NH }_{ 3 }^{ + }\), which is m-directing

(c)

-NH₂ becomes -NH+ \({ SO }_{ 4 }^{ - }\) , which is m-directing

(d)

-NH₂ becomes -NH^- \({ NO }_{ 2 }^{ + }\), which is m-directing

24.

Anilinium hydrogen sulphate on heating with sulphuric acid at 453-473 produces

(a)

benzenesulphonic acid

(b)

anthranilic acid

(c)

anline

(d)

m-aminobenzenesulphonic acid

(e)

sulphanilic acid

25.

\({ C }_{ 6 }{ H }_{ 5 }COOH \ \overset { 1.{ NH }_{ 3 } }{ \underset { 2.\triangle }{ \longrightarrow } } P\overset { NaOBr }{ \longrightarrow } Q\quad \overset { 1. \ Conc.{ H }_{ 2 }{ SO }_{ 4 } }{ \underset { 2. \ heat\ \ to\ \ 460\ \ K }{ \longrightarrow } } \ \ \ \ R\) 'R' is

(a)

o-bromosulphanilic acid

(b)

sulphanilamide

(c)

sulphanilic acid

(d)

p-bromosulphanilamide

26.

What reagent is used in Hinsberge test of amines?

(a)

(CH₃CO)₂O and pyridine

(b)

C₆H₅SO₂CI in aq.NaOH

(c)

NaNO₂ in aq.H₂SO₄

(d)

CH₃I (excess) followed by AgOH

27.

During the preparation of arenediazonium salts, the excess of nitrous acid, if any, is destroyed by adding.

(a)

Aq.NaOH

(b)

Aq.Na₂CO₃

(c)

Aq.NH₂CONH₂

(d)

Aq.KI

28.

Which of the following diazonium salt is most stable?

(a)

p-Nitrobenzenediazonium chloride

(b)

2, 4-Dinitrobenzenediazonium chloride

(c)

2, 4, 6-Trinitrobenzenediazonium chloride

(d)

p-Methoxybenzenediazonium chloride

29.

Which of the following will be the most stable diazonium salt, \({ RN }_{ 2 }^{ + }{ X }^{ - }\) ?

(a)

\(CH_{ 3 }{ N }_{ 2 }^{ + }{ X }^{ - }\)

(b)

\({ C }_{ 6 }H_{ 5 }{ N }_{ 2 }^{ + }{ X }^{ - }\)

(c)

\(CH_{ 3 }{ CH }_{ 2 }{ N }_{ 2 }^{ + }{ X }^{ - }\)

(d)

\({ C }_{ 6 }H_{ 5 }{ CH }_{ 2 }{ N }_{ 2 }^{ + }{ X }^{ - }\)

30.

Reduction of benzenediazonium chloride with Zn/HCI hives

(a)

aniline

(b)

phenylhydrazine

(c)

azobenzene

(d)

hydrazobenzene

31.

A positive carbylamine test is given by

(a)

N, N-dimethylaniline

(b)

2, 4-dimethylaniline

(c)

N-methyl-o-methylaniline

(d)

p-methylbenzylamine

32.

p-Chloroaniline and anilinium hydrochloride can be distinguished by

(a)

Sandmeyer reaction

(b)

NaHCO₃ solution

(c)

AgNO₃ solution

(d)

Carbylamine reaction

33.

Which of the following products is formed in the given reaction?

(a)

RNH₂

(b)

RCH₂NH₂

(c)

RCH₂CH₂NH₂

34.

Name the product(s) formed during the reaction of primary aliphatic amines with nitrous acid at room temperature?

(a)

\(\begin{equation} R \mathrm{~N}_{2}^{+} \mathrm{Cl^-} \end{equation}\)

(b)

ROH

(c)

Both (a) and (b)

(d)

None of the above

35.

Which of the following reactions is/are electrophilic substitution?

(a)

Bromination of aniline

(b)

Nitration of aniline

(c)

Sulphonation of aniline

(d)

All of the above

36.

Which of the following products is formed in the given reaction?

(a)

(b)

(c)

(d)

37.

Benzene diazonium chloride when reacts with hypophosphorus acid produces

(a)

Benzene

(b)

Phenol

(c)

Phenol isocyanide

(d)

Phenyl phosphate

38.

Which of the following compound will not undergo azo coupling reaction with benzene diazonium chloride?

(a)

Aniline

(b)

Phenol

(c)

Anisole

(d)

Nitrobenzene

39.

The correct name for yellow dye is

(a)

p-hydroxy azobenzene

(b)

p-amino azobenzene

(c)

o-hydroxyazobenzene

(d)

o-amino azobenzene

40.

In the reaction C₆H₅CONH₂ \(\xrightarrow[{\triangle }]{Br_2+KOH}\)Major product A is

(a)

C₆H₆

(b)

C₆H₅CHO

(c)

C₆H₅NH₂

(d)

C₆H₅COOKI

41.

(a)

\(\beta\)-Alanine

(b)

\(\alpha\)-Alanine

(c)

Ethylene diamine

(d)

Oxamide

42.

The reaction of P:Toluidine with CHCl₃ and KOH gives

(a)

(b)

(c)

(d)

43.

\(^{\prime} \mathrm{A}^{\prime}\stackrel{\text { Reduction }}{\longrightarrow}{ }^{\prime} \mathrm{B}^{\prime} \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
The compound' A' is

(a)

propane nitrile

(b)

ethane nitrile

(c)

nitro methane

(d)

methyl isocyanate

44.

4-Nitrotoluene is treated with bromine to get P. 'P' is reduced with Sn/HCI to get compound 'Q'. 'Q' is diazotised and the product is treated with phosphinic acid to get compound 'R'. 'R' is oxidised with alkaline KMnO₄ to get 'S'. Compound'S' is

(a)

2-Bromo-4-hydroxy benzoic acid

(b)

2-Bromo benzoic acid

(c)

3-Bromo benzoic acid

(d)

4-Bromo benzoic acid

45.

The product of the following reaction is ___________

(a)

(b)

(c)

(d)

46.

The most reactive amine towards dilute hydrochloric acid is ___________

(a)

CH₃ - NH₂

(b)

(c)

(d)

47.

Acid anhydrides on reaction with primary amines give ____________

(a)

amide

(b)

imide

(c)

secondary amine

(d)

imine

48.

Among the following amines, the strongest Bronsted base is _____________

(a)

(b)

NH₃

(c)

(d)

49.

Which of the following should be most volatile?
(I) CH₃CH₂CH₂NH₂
(II) (CH₃)₃N

(IV) CH₃CH₂CH₃

(a)

(b)

(c)

(d)

III

50.

Benzene diazonium chloride on hydrolysis gives.

(a)

Phenol

(b)

Chlorobenzene

(c)

Benzene

(d)

Aniline

Visit QB365-SLMS - https://www.qb365.in/slms/

Answers Key:

Multiple Choice Question

Benzylamine is most basic

Carbylamine reaction yields isocyanides.

(a)
\({ C }_{ 2 }{ H }_{ 5 }NCS\)

(b)
CH₄

Sulphonilic acid exists as a zwitterion.

(b)
LiAIH₄ in ether

-NO₂ is a m-directing group and hance 1, 3-dinitrobenzene is formed.

Electrolytic reduction of nitrobenzene in strongly acidic medium gives p-aminophenol.

-NO₂ is a powerful dectivating group. It reduces the electron density in the benzene ring considerably. As a result, it does not undergo F.C.reactions.

10.

Aniline cannot be prepared by Gabriel phthalimide method because chlorobenzene (i.e.,aryl halide) does not undergo nucleophilic substitution reaction with potassium phthalimide in aqueous NaOH solution.

11.

(c)
\(m-Br{ C }_{ 6 }{ H }_{ 4 }COOH\ \overset{ SOCI_{ 2 } }{ \longrightarrow } \quad \overset { NH_{ 3 } }{ \longrightarrow } \quad \overset { Br_{ 2 },NaOH }{ \longrightarrow } \)

12.

(a)
a primary amine

13.

In the gaseous phase, basicity increases as the + I-effect of the alkyl groups increases, i.e., CH₃NH₂(I) < (CH₃)₂ NH < (CH₃)₃ N (III). However, due to -I-effect of the CH- group, CHCHNH (IV) is even a weaker base than CHNH (I). Thus, the overall, basic character increases in the order : IV < I < II < III.

14.

Aliphatic/alicyclic amines are more basic than aromatic amines. Therefore, cyclohexylamine is most basic.

15.

All aliphatic amines are more basic than benzenamine. Further, due to the presence of two CH₃ groups on N in N, N-dimethylaniline, it is more basic than aniline or benzenamine. Hence, benzenamine is the weakest base base and hence has the highest pK_b value.

16.

A strongest base has the smallest pK_b, i.e. option (b) is correct.

17.

Amines are stronger bases than amines followed by amines. Further, among amines, (C₂H₅)₂NH is more basic than (CH₃)₂NH due to stronger +I-effect of the CH₃CH₂ over CH₃ group. Thus, option (b) is correct.

18.

19.