1325 g or 1 kg 325 g

Total cost of 20 flats = 348642060
Cost of each flat = 348642060 + 20 = Rs. 17432103

Distance covered in one day = 365 m
Number of days = 120
So, total distance covered by Tony in 120 days
= 365 \(\times\) 120 m = 43800 m
∴ Estimated product = 44000 m = 44 km

According to the Indian and International system of numeration, 2004004

We can make many situations of this kind, five situations of them are as follows:
Situation 1. Marry is a maid (servant). She charges Rs. 8 per day to clean a house but gives back Rs. 3 to the house owner for saving. What amount does she carry in her hand from 7 houses?
Situation 2. Ankit's pocket money is Rs. 8 per day. He spents Rs. 3 daily. Find his total saving in 7 days.
Situation 3. What will be the seven times the difference of eight and three?
Situation 4. A clerk works 8 h daily in an office, but he remains absent for 3 h daily. In a week, for how many hours did he work?
Situation 5. Seven children with Rs. 8 each went to market. Each of them bought pencils costing Rs. 3. What is total money left with them?

We have, 439 + 334 + 4317
\(\therefore \begin{matrix} 439\rightarrow 400 \\ 334\rightarrow 300 \\ 4317\rightarrow 4300 \end{matrix}\} [rounding\quad off\quad to\quad nearest\quad hundreds]\)
∴ Rough estimate = 439 + 334 + 4317
= 400 + 300 + 4300 = 5000
\(Again\begin{matrix} 439\rightarrow 440 \\ 334\rightarrow 330 \\ 4317\rightarrow 4320 \end{matrix}\} [rounding\quad off\quad to\quad nearest\quad tens]\)
and closer estimate = 439 +334 +4317
= 440 + 330 + 4320 = 5090

Rs. 16570

Given, distance between the school and the house
= 1 km 875 m =1\(\times\)1000+875
= 1000 + 875 = 1875 m [∵ 1 km = 1000 m]
∴ Distance covered by the student in one day
= 2\(\times\) 1875 = 3750 m [∵ She walks both ways in one day]
∴ Distance covered in 6 days = 6 x 3750
= 22500 m = (22 \(\times\) 1000 + 500) m
= 22 km 500 m    [∵1 km = 1000 m]

Using the digits 6, 2, 7, 4 and 3, we get
Greatest number = 76,432 and least number = 23,467
∴ Difference = Greatest number - Least number
=76,432 - 23,467 = 52,965.

Given, weight of one tablet = 20 mg
Total weight of 200000 tablets in the box = 200000 \(\times\) 20 mg
=4000000 mg
Now, weight in grams =\(\frac{4000000}{1000}g=4000g\) \(​​\left[ \because \quad 1mg=\frac { 1 }{ 1000 } g \right] \)
Now, weight in kilograms =\(\frac{4000}{1000}kg=4kg\) \(​​\left[ \because \quad 1g=\frac { 1 }{ 1000 } kg \right] \).

In 4942, ones digit is 2 < 5.
Then, rounded form of 4942 = 4940

The place value of 6 in 762540 = 6 \(\times\)10000
=60000

Expanded form of given numbers as
76496 = 7 \(\times\) 10000 + 6 \(\times\) 1000 + 4 \(\times\) 100 + 9 \(\times\) 10 + 6

Here, given digits are 3, 5, 4, 6. For the smallest number, we write the digits in ascending order. So, the smallest four-digit number is 3456.

199

8000

80000

According to the question, sum of 9 and 2 = 9 + 2
Now, mutiplying it by 4, we have 4 \(\times\) (9 + 2)
which is the required expression.

∵ 28,292 ⟶ 28,000[rounding off to nearest thousands]
21,496 ⟶ 21,000 [rounding off to nearest thousands]
∴ Estimated difference = 28000 - 21000 = 7000

We have, 92 = XCII  [∵ 92=100-10+1+1 i.e.100=C,10=X, 1 = I]

m 5 cm

According to the question,
A garment factory produced shirts = 216315
Produced trousers = 182736
Produced jackets = 58704
∴Total production of all the three items in that year
= Sum of all items
= 216315 + 182736 + 58704 = 457755
Hence, the total production of all the three items in that year is 457755.

According to the question,
Digit at ten's place = 4
Digit at unit's place = \(\frac{1}{4}\) of ten's place digit =\(\frac{1}{4}\times4=1\)
Digit at hundred's place = 0
Digit at thousand's place = 5 x Digit of unit's place
=5\(\times\)1=5
Digit at ten thousand's place = 2 x Digit of ten's place
=2\(\times\)4=8
∴ Required number = 85041

Given, Chinmay's total money =Rs.6,10,000
Money given to Jyoti by Chinmay = Rs. 87,500
Money given to Javed by Chinmay =Rs. 1,26,380
Money given to John by Chinmay = Rs. 3,50,000
∴ Money left with Chinmay = Total money - Distributed money
=6,10,000 -(87,500 + 1,26,380 + 3,50,000)
= 6,10,000 - 5,63,880 =Rs. 46,120
Hence, Rs. 46,120 was left with him.
The value depicted by Chinmay is that he is helpful nature towards his friends.

Given, total money = Rs.10,00,000
Money spent on a colour TV = Rs. 16,580
Money spent on a motorcycle = Rs. 45,890
and money spent on a flat = Rs. 8,70,000
Total amount spent = 16,580 + 45,890 + 8,70,000
= Rs. 9,32,470
∴ Money left with him = 10,00,000 - 9,32,470
= Rs.67,530
Hence, Rs. 67,530 was left with him.

Number of days in
November, 2009 = 30
25 x 30 = 750

100 x 89 = 8900
100 x 79 = 7900
8900 - 7900 = 1000

1 m 25 cm = 125 cm
10 m = 1000 cm
1000 ÷ 125 = 8

Difference = 20975 - 15875 = 5100

Difference = 10,000 - 9999 = 1

Total expenditure = 2725 + 2275 = 5000