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Published on: 24/10/2025
Download CBSE Class 6th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 6th Standard CBSE Mathematics
Questions + Answers key
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1.
If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.
2.
Find the difference of 4962 and 999 by suitable rearrangement.
3.
Find the value of 92165 x 179 - 92165 x 79.
4.
Write the five numbers, which can be shown as rectangle.
5.
Show some whole numbers can also be arranged as a triangle.
6.
A farmer plants 15 rows of trees. Each row has 12 trees. Find the total number of trees planted by the farmer.
7.
Write down the two whole numbers, which are on the right of 3 and on the left of 6.
8.
Write the successor of
(a) 2440701
(b) 100199
(c) 1099999
(d) 2345670.
9.
Find the sum, using the number line 2 + 6.
10.
Find the value of the following on the number line 3 + 6.
11.
Study the following patterns.
1 =12, 1 + 3 = 22, 1 + 3 + 5 = 32, 1 + 3 + 5 + 7 = 42
Hence, find the sum of
(a) First 19 odd numbers.
(b) First 21 odd numbers.
12.
Write the following numbers as directed using dots.
(a) 16 as a square
(b) 26 as a rectangle.
13.
In each of the following pairs of numbers, state which whole number is to the left of the other on the number line. Use appropriate symbol (> or <).
(a) 497, 495
(b) 3059, 3096.
14.
Write the predecessor of the following:
(a) 96
(b) 9998.
15.
Some numbers can be shown by two rectangles.
e.g. .png)
Give at least five other such examples.
16.
Find 15 x 68, 17 x 23, 69 x 78 + 22 x 69 Using distributive property
17.
Sudhir bought 10 TV sets at a rate of Rs 2000 for one set. He sells them in Rs 25000. Find his profit.
18.
Study the following patterns.
1 = 12
1 + 3 = 22
1 + 3 + 5 = 32
1 + 3 + 5 + 7 = 42
Hence, find the sum of
(a) first 12 odd numbers
(b) first 50 odd numbers.
19.
Which of the following numbers cannot be shown by two rectangles?
12
16
18
15
20.
Which of the following numbers can be shown as square?
11
12
13
16
21.
Find (24 \(\div\) 4 )\(\div\) 2.
1
3
4
2
22.
The difference between the successor of a number and the number itself is
0
-1
1
None of these
23.
The product of two whole numbers is always a
natural number
even number
odd number
None of these
24.
A whole number is added to 25 and the same number is subtracted from 25. The sum of the resulting numbers is
0
25
50
75
25.
24 x 25 = 24 x \(\frac{\Box}{4}\) = 600.
26.
1785 x 3 + 1785 x 7 = ___________.
27.
Division of whole number by __________ is not defined.
28.
300 is the predecessor of ____________.
1.
Yes For Example
2 x 0 = 0
0 x 3 = 3
0 x 0 = 0
2.
We have, 4962 - 999 = 4962 - (1000 -1) [\(\therefore\)999 = 1000 -1]
= (4962 -1000) + 1= 3962 + 1= 3963
3.
We have, 92165 x 179 - 92165 x 79
= 92165 (179 - 79) [taking 92165 as common term]
= 92165 x 100
= 9216500.
4.
6, 8, 10, 12, 14
5.

6.
180.
7.
4, 5.
8.
The successor of given numbers are as follows:
| Given number | Successor | |
| (a) | 2440701 | 2440701 + 1 = 2440702 |
| (b) | 100199 | 100199 + = 100200 |
| (c) | 1099999 | 1099999 + 1 = 1100000 |
| (d) | 2345670 | 2345670 + 1 = 2345671 |
9.
To find 2 + 6
Let us start from 2. Since, we have to add 6 to this number, we make 6 jumps to the right of 2. Each jump being equal to 1 unit. After six jumps, we reach at 8.
.png)
\(\therefore\) 2 + 6 = 8.
10.
For 3 + 6, start from 3 and make 6 jumps to the right by unit distance each. Then, we reach at 9.
.png)
So, 3 + 6 = 9.
11.
(a) 361
(b) 441.
12.
According to the patterns of whole number,

13.
We know that, the number which lies to the right of other is a greater number.
(a) 497 lies to the right of 495, so, 497 > 495
(b) 3059 lies left to the 3096, so, 3059 < 3096.
14.
We know that, predecessor is one less than the given whole number.
(a) Predecessor of 96 = 96 - 1 = 95
(b) Predecessor of 9998 = 9998 - 1 = 9997.
15.
There are many examples of such type. Five of them are as follows:
(i).png)
(ii).png)
16.
15 x 68 = 15 x (60 + 8)
= 15 x 60 + 15 x 8
(distributivity of multiplication over addition)
= 900 + 120 = 1020
17 x 23 = 17 x (20 + 3)
= 17 x 20 + 17 x 3
(distributivity of multiplication over addition)
=340+51=391
69 x 78 + 22 x 69
= 69 x 78 + 69 x 22
(commutativity of multiplication)
= 69 x (78 + 22)
(distributivity of multiplication over addition)
= 69 x 100 = 6900.
17.
Rs 5000
18.
The given pattern is
1 = 12
1 + 3 = 22
1+ 3 + 5 = 32
1+ 3 + 5 + 7 = 42
(a) Sum of first 12 odd numbers
1+ 3 + 5 + 7 + 9 + 11 + 13 + 15 + 19 + 21 + 23 + 25 = 122 = 1
(b) Similarly, sum of first 50 odd numbers = 502 = 2500.
19.
(d)
15
20.
(d)
16
21.
(b)
3
22.
(c)
1
23.
We know that, the product of two whole numbers is always a whole number.
e.g. 0 x 0 = 0 and 1 x 2 = 2.
24.
Let the whole number be x.
Now, according to the question,
x + 25 + 25 - x = 50.
25.
( )
100
26.
We have,
1785 x 3 + 1785 x 7 = 1785 (3 + 7)
= 1785 x 10 = 17850.
27.
( )
0
28.
Here, we will find successor of 300, 300 + 1 = 301
So, 300 is the predecessor of 301.
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