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Published on: 28/05/2021
QB365 Provides the HOT Question Papers for Class 11 Chemistry, and also provide the detail solution for each and every HOT Questions. HOT Questions will help to get more idea about question pattern in every exams and also will help to get more marks in Exams
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Questions + Answers key
Take MCQ Chemistry Test1.
Neutrons can be found in all atomic nuclei except in one case. Which is this atomic nucleus and what does it consist of ?
2.
Explain why uncertainty principle is significant only for the motion of sub-atomic particle but is negligible for the macroscopic objects?
3.
Why AIF3 is a high melting solid whereas SiF4 is a gas?
4.
How many nodal planes are present in \(\pi ({ 2p }_{ x })\) and \( \pi{ \times}({ 2p }_{ x })\) molecular orbitals?
5.
Water can be lifted into the water tank at the top of the house with the help of a pump. Then why is it not considered to be spontaneous?
6.
Air contains about 99% of N2 and O2 gases. Why do not they combine to form NO under the standard conditions? Standard Gibbs energy of formation of NO (g) is 86.7 kJ mol-1.
7.
Why is anode called oxidation electrode, whereas cathode is called reduction electrode?
8.
Can Fe3+ oxidise Br- to Br2 at 1 M concentrations?
Eo(Fe3+ I Fe2+) = 0.77 V and Eo (Br I Br - ) = 1.09V
9.
What would have happened to the gas if the molecular collision were not elastic?
10.
Describe the bulk preparation of hydrogen by electrolytic method. What is the role of an electrolyte in this process?
1.
In case of hydrogen atom, there is no neutron. It consists of only one proton
2.
The energy of photon is sufficient to disturb a sub-automic particle so that there is uncertainty in the measurement of position and momentum of the sub-atomic particle. However the energy is insufficient to disturb a macroscopic object.
3.
AIF3 is an ionic compound whereas SiF4 is a non-polar covalent compound. Hence, interparticle forces in AIF3 are much stronger that's why it is a high melting solid.
4.
One and two respectively.
5.
A spontaneous process should occur continuously by itself after initiation. But this is not so in the given case because water will go up as long as the pump is working.
6.
For the combination of N2 and O2 to form NO, the standard Gibbs energy of formation, is +ve
1/2N2(g)+1/2O2(g)→NO(g)(ΔfG∘NO = +86.7 kJmol−1)
Therefore, this reaction is non-spontaneous under the standard conditions and hence N2 and O2 do not combine.
7.
At the anode, loss of electrodes takes place, ie. oxidation takes place, whereas cathode, a gain of electrodes takes place, ie. reduction takes place.Therefore, the cathode is called reduction electrode and anode is called oxidation electrode.
8.
Eo(Fe3+ I Fe2+)is lower than that of Eo (Br I Br - ).Therefore, Fe2+ can reduce Br2 bur Br - cannot reduce Fe3+. Thus, Fe3+ cannot oxidise Br - to Br2
9.
( )
On every collision, there would have been loss of energy.As a result, the molecules would have slowed down and ultimately settle down in the vessel.Moreover, the pressure would have gradually reduced to zero.
10.
( )
Electrolysis of acidified water using platinum electrodes gives hydrogen.
\(2{ H }_{ 2 }O(l)\overset { Electrolysis }{ \underset { Traces \ of \ acid/base }{ \rightarrow } } 2{ H }_{ 2 }(g)+{ O }_{ 2 }(g)\\ \)
Here, the role of an electrolyte is to make water conducting.
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