CBSE 11th Standard Maths Subject Probability Ncert Exemplar 4 Marks Questions 2021
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CBSE 11th Standard Maths Subject Probability Ncert Exemplar 4 Marks Questions 2021
11th Standard CBSE
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Reg.No. :
Mathematics
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One card is drawn from a well-shuffled deck of 52 cards.Calculate the probability that the card will be
an ace(a) -
One card is drawn from a well-shuffled deck of 52 cards.Calculate the probability that the card will be
a black card(a) -
One card is drawn from a well-shuffled deck of 52 cards.Calculate the probability that the card will be
not an ace(a) -
Suppose an integer from 1 through 1000 is chosen at random.Find the probability that the integer is a multiple of 2 or a multiple of 9.
(a) -
A die is rolled in such a way that each odd number is twice as likely to occur as likely to occur as each even number.Find P(G), where G is the event that a number greater than 3 occurs on a single roll of the die.
(a)
4 Marks
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CBSE 11th Standard Maths Subject Probability Ncert Exemplar 4 Marks Questions 2021 Answer Keys
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\(\frac { 1 }{ 13 } \)
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\(\frac { 1 }{ 2 } \)
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\(\frac { 12 }{ 13 } \)
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0.556
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When a die is rolled , then we get 1 or 2 or 3 or 4 or 5 or 6.
S = {1,2,3,4,5,6}
It is given that
P(each odd number = 2 x P (each even number)
P(1) = 2x, P(2) = x, P(3) = 2x ,P(4) = x, P(5) =2x and P(6) = x
We know that , P(5) = 1
P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1
\(\Rightarrow \) 2x + x + 2x + x + 2x + x = 1 \(\Rightarrow \) \(x=\frac { 1 }{ 9 }\)
Thus P(1) = P(3) = P(5) = \(\frac { 2 }{ 9 } \)
and P(2) = P(4) = P(6) = \(\frac { 1 }{ 9 } \)
Now, P(G) = P (getting 4 or 5 or 6)
= P(4) + P(5) +P(6) = \(\frac { 4 }{ 9 } \)
4 Marks
