Sample space
S = {HHH, HHT, HTH, HTT, THT, TTH, THH, TTT}
\(\therefore \) Total number of sample space, n(S) = 8
There are three favourable cases for exactly 2 heads
HHT, HTH, THH.
\(\therefore \)  P(exactly 2 heads) = \(\frac { 3 }{ 8 } \)

Sample space
S = {HHH, HHT, HTH, HTT, THT, TTH, THH, TTT}
\(\therefore \) Total number of sample space, n(S) = 8
Atleast 2 heads \(\Rightarrow \) 2 or 3 heads
\(\therefore \) There are four favorable cases
[HHT, HTH, THH, HHH]
\(\therefore \) P (atleast 2 heads) =\(\frac { 4 }{ 8 } =\frac { 1 }{ 2 } \)

Sample space
S = {HHH, HHT, HTH, HTT, THT, TTH, THH, TTT}
∴ Total number of sample space, n(S) = 8
P(atmost 2 heads) = P(not 3 heads)
=1 - P(3 head)
= 1-\(\frac { 1 }{ 8 } \)=\(\frac { 7 }{ 8 } \)

Sample space
S = {HHH, HHT, HTH, HTT, THT, TTH, THH, TTT}
∴ Total number of sample space, n(S) = 8
P(no head) = P (all tails) = \(\frac { 1 }{ 8 } \)

When a cricket game starts, then the coin is tossed between the two captains of the teams and the captain who wins, decide either to bat or to ball.