CBSE 11th Standard Physics Subject Thermal Properties of Matter HOT Questions 5 Mark Questions With Solution 2021
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CBSE 11th Standard Physics Subject Thermal Properties of Matter HOT Questions 5 Mark Questions With Solution 2021
11th Standard CBSE
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Reg.No. :
Physics
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Aman went for a weekend trip with his parents and grandparents to a remote village. His grandfather showed him the fields and the crops they grow. As they moved forward, they saw that a bullock cart got struck in wet mud and the driver was not able to push it out by himself. Seeing him in distress, Aman ran to his help and together they pushed it out, but iron rim of the wheel came out.
They tried to put it on the wheel but it was smaller than diameter of wheel. Suddenly, he got an idea. He collected some wood and set them on fire and heated the rim and then rim easily slipped on the wheel. Cartman thanked Aman and moved away.
(i) What values of Aman does the incident show?
(ii) If the diameter of the rim and ring were 5.243 m and 5.231 m respectively at 27 \(^{0}\)C. To what temperature had Aman heated the ring so as to fit the rim of the wheel? Coefficient of linear expansion of iron = 1.20 x 10-5 K-1
(iii) Which property of solids is used in this phenomenon?(a) -
Kavita was overweight. At the age of 16 yr. She weighted 70 kg. He friends used to laugh at her and she felt very embarrassed. She then decided that she would loose weight and would become fit and fine like others. She started walking daily for 30min and stopped eating food. She started taking only few fruits and milk. Her parents advised her not cut-off her meal so drastically but she didn't listen to anybody.
The result was that she lost 30 kg weight but now she felt very weak and was not able to eat anything.Ultimately, her parents took her to a doctor who advised her to take proper balanced diet and to do exercise.
(i) Do you think taking crash diet is advisable? Justify.
(ii) If Kavita, weighing 60 kg now, was advised 2000 kcal diet in a day and this energy was to be used in heating her without any losses, what would be her rise in temperature? (Given, specific heat of human body is 0.83 cal g-1 oC -1)
(iii) What is the relation between SI and CGS unit of heat?(a)
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CBSE 11th Standard Physics Subject Thermal Properties of Matter HOT Questions 5 Mark Questions With Solution 2021 Answer Keys
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(i) Aman loves nature and his helpful boy. He also has presence of mind as he thought of an excellent idea to help cartman.
(ii) \({ L }_{ 1 }=5.231m,{ L }_{ 2 }=5.243m,{ T }_{ 1 }=27 ^{0}C,{ T }_{ 2 }=?\)
As we know
\(\therefore { T }_{ 2 }-{ T }_{ 1 }=\frac { { L }_{ 2 }-{ L }_{ 1 } }{ { L }_{ 1 }\times \alpha } \)
\(\\ { T }_{ 2 }=\frac { { L }_{ 2 }-{ L }_{ 1 } }{ { L }_{ 1 }\alpha } \)
\({ T }_{ 2 }=\frac { 5.243-5.231 }{ 5.231\times 1.2\times { 10 }^{ -5 } } +27\)
\(\\ =218 \ ^{0} C\)
(iii) Linear expansion of solids i.e increase in length of solid on heating. -
(i) Crash diet means making the body deficient in certain nutrients which is harmful for body as it requires balanced diet to work. Crash diet should not be taken as it makes body weak and less immune to diseases.
(ii) \(m=60\quad kg=60\times { 10 }^{ 3 }g\)
\(\Delta Q=2000k\quad cal=2\times { 10 }^{ 6 }cal\)
\(\Delta T=?,\quad c=0.83cal{ g }^{ -1 }\)\(^{0}\)C-1
From \(\Delta Q=cm\Delta T,\)
\(\Delta T=\frac { \Delta Q }{ cm } =\frac { 2\times { 10 }^{ 6 } }{ 0.83\times 60\times { 10 }^{ 3 } } =40.16^{ o }C\)
(iii) SI unit = joule
CGS unit = calorie
1 calorie = 4.18 J
