CBSE 12th Standard Chemistry Subject Amines Chapter Case Study Questions 2021
By QB365 on 21 May, 2021
QB365 Provides the updated CASE Study Questions for Class 12 , and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get more marks in Exams
QB365 - Question Bank Software
CBSE 12th Standard Chemistry Subject Amines Case Study Questions 2021
12th Standard CBSE
-
Reg.No. :
Chemistry
-
Read the passage given below and answer the following questions:
Amines are basic in nature. The basic strength of amines can be expressed by their dissociation constant, Kb or pKb.
\(\mathrm{RNH}_{2}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{RNH}_{3}^{+}+\mathrm{OH}^{-}\)
\(K_{b}=\frac{\left[R \mathrm{NH}_{3}^{+}\right]\left[\mathrm{OH}^{-}\right]}{\left[R \mathrm{NH}_{2}\right]} \text { and } \mathrm{p} K_{b}=-\log K_{b}\)
Greater the Kb value or smaller the pKb value, more is the basic strength of amine. Aryl amines such as aniline are less basic than allphatic amines due to the involvement of lone pair of electrons on N-atom with the resonance in benzene. In derivatives of aniline, the electron releasing groups increase the basic strength while electron withdrawing groups decrease the basic strength. The base weakening effect of electron withdrawing group and base strengthening effect of electron releasing group is more marked at p-position than at m-position. o-Substituted aniline is less basic than aniline due to ortho effect and is probable due to combination of electronic and steric effect.
The following questions are multiple choice questions.Choose the most appropriate answer :
(i) Which of the following has lowest pKb value?(ii) The strongest base among the following is
(a) C6H5NH2 (b) p-NO2 - C6H4CH2NH2 (c) m-NO2 - C6H4NH2 (d) C6H5NH2 (iii) Maximum pKb value of
(c) (CH3CH2)2NH (d) (CH3)2NH (iv) Which of the following statements is not correct?
(a) Methylamine is more basic than NH3 (b) Amines form hydrogen bonds. (c) Ethylamine has higher boiling point than propane. (d) Dimethylamine is less basic than methylamine. (a) -
Read the passage given below and answer the following questions:
RCONH2 is converted into RNH2 by means of Hoffmann bromamide degradation. During the reaction amide is treated with Br2 and alkali to get amine. This reaction is used to descend the series in which carbon atom is removed as carbonate ion (CO32-). Hoffmann bromide degradation reaction can be written as :
The following questions are multiple choice questions. Choose the most appropriate answer:
(i) Hoffmann bromamide degradation is used for the preparation of(a) primary amines (b) secondary amines (c) tertiary amines (d) secondary aromatic amines. (ii) Which is the rate determining step in Hoffmann bromamide degradation?
(a) Formation of (i) (b) Formation of (ii) (c) Formation of (iii) (d) Formation of (iv). (iii) Which of the following are used for the conversion of (i) to (ii)?
(a) KBr (b) KBr + CH3ONa (c) KBr + KOH (d) Br2 + KOH (iv) What are the constituent amines formed when the mixture of (i) and (ii) undergoes Hoffmann bromamide degradation?
(a) -
Read the passage given below and answer the following questions:
Amines are produced when an alcoholic solution of ammonia and an alkyl or a benzyl halide is heated in a sealed tube at 373 K. This reaction is called ammonolysis and usually gives a mixture of primary, secondary and tertiary amines along with some quarternary ammonium salts. This reaction is an example of nucleophilic substitution reaction in which ammonia acts as a nucleophile due to the presence of a lone pair of electrons on the nitrogen atom. However this method cannot be used for the preparation of aryl amines. One of the most convenient methods for the preparation of aryl amines is reduction of nitro compounds. Aryl amines can also be prepared by reduction of nitrites or Gabriel phthalimide synthesis.
In these questions (i-iv), a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
(a) Assertion and reason both are correct statements and reason is correct explanation for assertion.
(b) Assertion and reason both are correct statements but reason is not correct explanation for assertion.
(c) Assertion is correct statement but reason is wrong statement.
(d) Assertion is wrong statement but reason is correct statement. .
(i) Assertion: Ammonolysis of alkyl halides only produces 2o amines.
Reason: Ammonolysis of alkyl halides involves the reaction between alkyl halides and alcoholic ammonia.
(ii) Assertion: Ammonolysis method cannot be used for the preparation of aryl amines.
Reason: Aryl halides are much less reactive than alkyl halides towards nucleophilic substitution reaction.
(iii) Assertion: Ammonolysis can be used to prepare pure primary amines.
Reason: Ammonolysis of haloalkanes lead to multiple ammonium salts.
(iv) Assertion: Aromatic 1p amines can not be prepared by Gabriel phthalimide synthesis.
Reason: Aryl halides do not undergo nucleophilic substitution with anion formed by phthalimide.(a) -
Read the passage given below and answer the following questions:
Aniline activates the benzene ring by increasing electron density at ortho- and para-positions. Hence, it is o-, p-directing. -NH2 group strongly activates the ring therefore it is difficult to stop the reaction at monosubstitution stage. Among electrophilic substitution reaction, direct nitration of aniline is not done to get o- and p-nitroaniline because lone pair of electrons present at nitrogen atom will accept proton from nitrating mixture to give anilinium ion which is meta-directing. Aniline with NaNO2 and HCl forms benzene diazonium chloride at very low temperature. Aromatic amines react with nitrous acid to form a yellow oily liquid known as N-nitrosoamines.
In these questions ( i-iv), a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
(a) Assertion and reason both are correct statements and reason is correct explanation for assertion.
(b) Assertion and reason both are correct statements but reason is not correct explanation for assertion.
(c) Assertion is correct statement but reason is wrong statement.
(d) Assertion is wrong statement but reason is correct statement.
(i) Assertion: Nitrating mixture used for carrying out nitration of benzene consists of cone. conc. HNO3 +conc. H2SO4 .
Reason: In presence of H2SO4 , HNO3 acts as a base and produces NO2+ ions.
(ii) Assertion: Anilinium chloride is more acidic than ammonium chloride.
Reason: Anilinium ion is not resonance-stabilised.
(iii) Assertion: Nitrobenzene can be prepared from benzene by using mixture of conc. HNO3 and conc. H2SO4 .
Reason: In the mixture,H2SO4 act as a acid.
(iv) Assertion: In strongly acidic solution, aniline becomes less reactive towards electrophilic reagents.
Reason: The amino group being completely protonated in strongly acidic solution, the lone pair of electrons on the nitrogen is no longer available for resonance.(a)
*****************************************
CBSE 12th Standard Chemistry Subject Amines Case Study Questions 2021 Answer Keys
-
(i) (c)
(ii) (d)
(iii) (a)
(iv) (d): Dimethylamine is more basic than methyl amine. -
(i) (a)
(ii) (d): The rate determining step is probably loss of Br- to form isocyanate as this is the slowest step.
(iv) (b): Since, the overall reaction is intermolecular, hence there will be no effect on product formation.
-
(i) (d): Reaction can be used to prepare 1°, 2°, 3° amines and finally quaternary ammonium salts.
(ii) (a)
(iii) (d): Ammonolysis cannot be used to prepare pure primary amines. This method usually gives a mixture of primary, secondary and tertiary amines along with some quaternary ammonium salts.
(iv) (a) -
\(\text { (i) }(\mathrm{a}): \mathrm{HNO}_{3}+2 \mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons 2 \mathrm{HSO}_{4}^{-}+\mathrm{NO}_{2}^{+}+\mathrm{H}_{3} \mathrm{O}^{+}\)
(ii)(c) : \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}^{+} \longrightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+\mathrm{H}^{+}\)
anilinium ion aniline
stronger acid weaker conjugated base
Aniline is weaker base than ammonium chloride. In NH4CI or aliphatic amines, the non-bonding electron pair of N is localized and is fully available for coordination with a proton. On the other hand, in aniline or other aromatic amines, the non-bonding electron pair is delocalised into benzene ring by resonance.
But anilinium ion is less resonance stabilised than aniline.
(iii) (b)
(iv) (a)