CBSE 12th Standard Chemistry Subject The p-Block Elements Ncert Exemplar 2 Mark Questions 2021
By QB365 on 25 May, 2021
QB365 Provides the updated NCERT Exemplar Questions for Class 12, and also provide the detail solution for each and every NCERT Exemplar questions. NCERT Exemplar questions are latest updated question pattern from NCERT, QB365 will helps to get more marks in Exams
QB365 - Question Bank Software
CBSE 12th Standard Chemistry Subject The p-Block Elements Ncert Exemplar 2 Mark Questions 2021
12th Standard CBSE
-
Reg.No. :
Chemistry
-
State reasons for each of the following:
(i) All the P-Cl bonds in PCl5 molecule are not equivalent.
(ii) Sulphur has greater tendency for catenation than oxygen.(a) -
Assign a reason for each of the following statements:
(i) More metal fluorides are ionic in nature than metal chlorides.
(ii) SCI6 is not known but SF6 is known.(a) -
Explain why the stability of oxoacids of chlorine increases in the order given below:
HCIO < HCIO2 < HCIO3 < HCIO4(a) -
Write a balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen.
(a) -
Write the structure of pyrophosphoric acid.
(a)
*****************************************
CBSE 12th Standard Chemistry Subject The p-Block Elements Ncert Exemplar 2 Mark Questions 2021 Answer Keys
-
(i) it is because all the bonds are not in same plane. Axial bonds are longer than equatorial bonds due to more repulsion.
(ii) It is because of strong S-S bond than O-O due to greater repulsion between valence electrons of smaller atoms of oxygen than sulphur atoms. -
(i) It is due to greater difference in electronegativity in fluorides than in chlorides.
(ii) In SCI6 there is more repulsion than in SF6, therefore, SCI6 does not exist. -
It is due to stability oxo anions follows the following order due to dispersal of charge on more number of electronegative oxygen atoms.
CIO- < CIO2- < CIO3- < CIO4- -
\(4{ NH }_{ 3 }+5{ O }_{ 2 }\xrightarrow [ 500K,9bar ]{ Pt/Rh\ gauze,catalyst } 4NO+6{ H }_{ 2 }O\)
-
\(HO-\overset { \underset { \parallel }{ O } }{ \underset { \overset { | }{ HO } }{ P } } -O-\overset { \underset { \parallel }{ O } }{ \underset { \overset { | }{ OH } }{ P } } -OH\) Pyrophosphoric \(\left( { H }_{ 4 }{ P }_{ 2 }{ O }_{ 7 } \right) \) acid