CBSE 12th Standard Maths Subject Matrices HOT Questions 6 Mark Questions With Solution 2021
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CBSE 12th Standard Maths Subject Matrices HOT Questions 6 Mark Questions With Solution 2021
12th Standard CBSE
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Reg.No. :
Maths
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If A = \(\left[ \begin{matrix} 3 & 1 \\ 7 & 5 \end{matrix} \right] \) find x, y such that A2 +xI = yA Hence find A-1
(a) -
If \(A=\left[ \begin{matrix} 1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & 1 \end{matrix} \right] \) Prove that , A =\(\left[ \begin{matrix} { 3 }^{ x-1 } & { 3 }^{ x-1 } & { 3 }^{ x-1 } \\ { 3 }^{ x-1 } & { 3 }^{ x-1 } & { 3 }^{ x-1 } \\ { 3 }^{ x-1 } & { 3 }^{ x-1 } & { 3 }^{ x-1 } \end{matrix} \right] \) for every positive integer n.
(a) -
The sum of three numbers is -1. If we multiply the second number by 2 , third number by 3 and add them we get 5. If we subtract the third number from the sum of first and second numbers we get -1. Represent it by a system of equations . Find the three numbers using inverse of a matrix
(a)
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CBSE 12th Standard Maths Subject Matrices HOT Questions 6 Mark Questions With Solution 2021 Answer Keys
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x =8 y = 8
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\({ A }^{ -1 }=\frac { 1 }{ 8 } \left[ \begin{matrix} 5 & -1 \\ -7 & 3 \end{matrix} \right] \)
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Let numbers be x, y, z then
x + y + z = -1
2y + 3z = 5
x + y – z = -1
\(x=-\frac { 7 }{ 2 } \), y = \(\frac { 5 }{ 2 } \), z = 0
