Class 11th Physics - Oscillation Case Study Questions and Answers 2022 - 2023
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Oscillation Case Study Questions With Answer Key
11th Standard CBSE
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Reg.No. :
Physics
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In our daily life, we come across various types of motions: such as periodic, non-periodic, oscillatory and non oscillatory. The study of oscillatory motion is of great importance as its concepts are required for the understanding of many physical phenomena, for example
(i) vibrating strings produces pleasant. sounds in musical instruments like the sitar, guitar or the violin
(ii) the oscillations of the atoms in solid about their mean positions to convey the sensation of temperature.
All oscillatory motions are periodic motions but all periodic motion may not be oscillatory. An oscillatory motion is further classified as harmonic and non-harmonic oscillation.
(i) What are oscillatory motions? Give example.
(ii) Give example of periodic motion which are not oscillatory.
(iii) Differentiate between harmonic and non-harmonic oscillations.
(iv) What causes a system to oscillate?
(v) On what factor does the time period of a simple harmonic oscillator depends?
(vi) What are periodic functions? Express one graphically.(a) -
Simple harmonic motion is a special type of periodic motion, in which a particle moves to and fro repeatedly about a mean position under a restoring force, which is always directed towards the mean position and whose magnitude at any instant is directly proportional to the displacement of the particle from the mean position at that instant i.e., Fresloring =-Kx, where K is force constant and x - the displacement of the particle executing S.H.M. It can be expressed in terms of one simple harmonic function x = a sin \(\left(\omega t+\phi_{0}\right)\) 0)' where a - is the amplitude of oscillation and \(\left(\omega t+\phi_{0}\right)\) is the phase of vibrating particle at the instant t, \(\phi_{0}\) is initial phase and co is the angular frequency of the vibrating particle in S.H.M.
(i) Give geometrical interpretation of S.H.M.
(ii) Express the velocity and acceleration of S.H.M in terms of displacement and angular frequency \((\omega)\).
(iii) State the condition when S.H.M particle velocity is in phase and opposite in phase with the acceleration of particle.
(iv) What is the average value of total energy of a particle in S.H.M in one complete oscillation?
(v) What is the frequency of P.E, K.E and total energy in S.H.M?
(vi) What will be the time period of second's pendulum if its length is doubled?
(vii) The girl sitting on a swing stands up. What will be the effect on the periodic time of the swing?(a) -
Consider two springs of spring constants KJ and K2 . Let there be three spring combinations as shown in fig (a), (b), and (c). A body of mass rn oscillates about its mean position under influence of restoring force (F) produced when displaced from the equilibrium position of the body.
(i) Determine the net restoring force and spring constant of the combination of spring in fig (a) for a displacement of y in mass from mean position.
(ii) Determine the spring constant of combination of spring in fig (b) and also the restoring force produced when displaced from mean position.
(iii) Determine the spring constant of combination of spring in fig (c) an,d also the restoring force produced when displaced from mean position.
(iv) Determine the frequency of oscillation in each of combination.(a) -
A body capable of oscillating S.H.M when displaced from mean position start oscillating. During oscillation amplitude of oscillating body may either vary or remain constant. It is categorised as undamped, damped and free or forced vibraton depending on whether there is some resistive force present in the medium where body is oscillating or not and also if the body under the influence of some external force or not. Amplitude of oscillation is function of resistive force of the medium, external periodic force and phase difference between external force and oscillating body.
(i) What are undamped simple harmonic oscillations?
(ii) Define damped oscillations. Give example.
(iii) What are free oscillations? On what factor does the natural frequency of an oscillating system depends?
(iv) What are forced oscillations?
(v) Give an example of forced oscillation.
(vi) What are resonant oscillations? Give example.
(vii) Is the damping force, constant on a system executing S.H.M?(a) -
A 2 kg block hangs without vibrating at the bottom end of a spring with a force constant of 800 N/m. The top end of the spring is attached to the ceiling of an elevator car. The car is rising with an upward acceleration of 10 ms-2. When the acceleration suddenly ceases at time t = 0, the car moves upward with constant speed. (g = 10 ms-2 )
(i) What is the angular frequency of oscillation of the block if their acceleration' ceases?
(ii) Determine the amplitude of the oscillation.
(iii) Determine the initial phase angle observed by a rider in the elevator, taking downward direction to be positive.
(iv) A particle starts oscillating from half the amplitude position. What is its initial phase?
(v) A simple harmonic motion of amplitude A, has a time period T. What will be the acceleration of the oscillator when its displacement is half of the amplitude?(a)
Case Study
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Answers
Oscillation Case Study Questions With Answer Key Answer Keys
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(i) Oscillatory motion are periodic motions that repeat itself after definite interval of time and occur about a mean position due to property of inertia and elasticity of oscillating body. e.g., vibration of strings of musical instrument, and motion of swing.
(ii) The revolution of earth around the sun and the motion of hands of a clock is a periodic motion but not oscillatory.
(iii) Harmonic oscillation is that oscillation which can be expressed in terms of single harmonic function (i.e., sine function or cosine function).
Non-harmonic oscillation cannot be expressed in terms of single harmonic function.
(iv) The oscillation of a physical system results from two basic properties of the system namely elasticity and inertia.
(v) The time period of a simple harmonic oscillator depend upon its inertial and elastic properties as follows.
T = \(2 \pi \sqrt{\frac{\text { Inertia factor }}{\text { Elastic factor }}}\)
(vi) Peridoc functions are those functions which are used to represent periodic motion. A functionJ(t) is said to be periodic, ifJ(t) = J(t + T) = J(t + 2T)
Sine and Cosine functions are the periodic function.
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(i) Simple harmonic motion is the projection ofa uniform circular motion on any diameter of a circle of reference x = a cos \(\theta=a \cos \omega t\) .
(ii) Velocity v = \(\omega \sqrt{a^{2}-y^{2}}\)
acceleration a = \(-\omega^{2} y\) .
(iii) The particle velocity in S.H.M is in phase with acceleration when particle is moving from extreme position to mean position and is in opposite phase with acceleration when particle is moving from mean position to extreme position.
(iv) Average value of total energy of a particle in S.H.M in one complete oscillation \(E_{a v}=\frac{1}{2} m w^{2} a^{2}\) .
(v) The frequency of PE and K.E is double than that of S.H.M while the frequency of total energy of particle in S.H.M is zero.
(vi) T = \(2 \pi \sqrt{\frac{l}{g}}\) = 2
T = \(2 \pi \sqrt{\frac{2 l}{g}}\)
= \(\sqrt{2} \times 2 \pi \sqrt{\frac{l}{g}}\)
= \(\sqrt{2} \times 2=2.828 \mathrm{sec}\).
(vii) The periodic time T will decrease because in the standing position, the location of CM of the girl shifts upwards. Due to which the effective length of the pendulum l becomes less. As T \(T \propto \sqrt{l}\). Therefore T decreases. -
(i) In fig (a) two springs are in parallel combination, Net restoring force is sum of restoring force produced in k1 and k2, for displacement y.
F = F1 + F2 = - (k1 + k2)y
therefore, spring constant of the combination is k = k1 + k2
(ii) Fig (b) is series combination of springs, therefore restoring force is same in each spring but both experience different extensions.
F = -k1y1 = -k2Y2
y = y1 + Y2
\(\Rightarrow \quad f=-\left(\frac{k_{1} k_{2}}{k_{1}+k_{2}}\right) y\)
there spring constant of the combination is
\(k=\frac{k_{1} k_{2}}{k_{1}+k_{2}}\)
(iii) Fig (c) is parallel combination of spring, therefore
Total restoring force F = -(k1 + k2 )y
and spring constant K = k1 + k2
(iv) In fig (a) v = \(\frac{1}{2 \pi} \sqrt{\frac{k}{m}}\)
= \(\frac{1}{2 \pi} \sqrt{\frac{k_{1}+k_{2}}{m}}\)
In fig (b) v = \(\frac{1}{2 \pi} \sqrt{\frac{k_{1} k_{2}}{m\left(k_{1}+k_{2}\right)}}\)
In fig (c) v = \(\frac{1}{2 \pi} \sqrt{\frac{k_{1}+k_{2}}{m}}\) -
(i) When a simple harmonic system oscillates with a constant amplitude which does not change with time, its oscillations are called undamped simple harmonic oscillations.
(ii) When a system of simple harmonic oscillates with decreasing amplitude with time its oscillation are called damped simple harmonic oscillations. The dissipative forces or damping forces are active in the system which are generally the frictional or viscous forces. For example, the oscillations of the bob of a simple pendulum in air or medium are damped oscillations.
(iii) A system capable of oscillating is said to be executing free oscillations if it vibrates with its own natural frequency without the help of any external periodic force. The natural frequency of vibration of system depends upon
(i) inertia facstor (m)
(ii) elastic properties and dimension of the system
(k) i.e., V0 = \(\frac{1}{2 \pi} \sqrt{\frac{k}{m}}\)
(iv) When a body oscillates with the help of an external periodic with a frequency different from the natural frequency of the body, its oscillations are called forced oscillations.
(v) Sound board of all stringed musical instruments like violin, sitar, etc. execute forced oscillations.
(vi) Phenomenon of increase in amplitude of oscillation when the frequency of the driving force is close to the natural frequency of the oscillator is called resonance. For example, the loud sound is heard due to resonant oscillation when the frequency of oscillations of the air column becomes equal to the frequency of the vibrating tuning fork.
(vii) No, because damping force depends upon velocity and is more when the system moves fast and is less when system moves slow. -
(i) Angular frequency
\(w=\sqrt{\frac{k}{m}}\)
= \(\sqrt{\frac{800}{2}}\)
= 20 rad/s
(ii) Maximum extension in the spring from mean position is x
then mg + ma = kx
\(\Rightarrow \quad x=\frac{m g+m a}{k}\)
= \(\frac{2(10+10)}{800}\) = 5 cm
Extension of the spring when it is stretched to equilibrium line x'
mg = kx'
\(\Rightarrow \quad x^{\prime}=\frac{m g}{k}\) = 25 cm
therefore amplitude,
A = x - x' = 2.5 cm.
(iii) If downward direction is taken as postive at t = 0, x = A
using x = A sin\((\omega t+\phi)\)
\(\Rightarrow \quad \phi=\frac{\pi}{2}\)
(iv) y = a sin\(\left(\omega t+\phi_{0}\right)\) , At t = 0, y = \(\frac{a}{2}\)
\(\therefore \quad \frac{a}{2}=a \sin \left(\omega \times 0+\phi_{0}\right)\)
= \(a \sin \phi_{0} \text { or } \sin \phi_{0}=\frac{1}{2}=\sin \frac{\pi}{6}\)
or \(\phi_{0}=\frac{\pi}{6}\)
(v) acceleration \(a=-\omega^{2} y\)
= \(\frac{-4 \pi^{2}}{T^{2}} \times \frac{A}{2}\)
= \(\frac{-2 \pi^{2} A}{T^{2}}\)
Case Study