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CBSE 9th Standard Mathematics Statistics Sample Question Papers Study Material - QB365 Set D

Published on: 29/10/2025

Question Set D

CBSE 9th Standard Mathematics Statistics Sample Question Papers Study Material - QB365

Download CBSE Class 9th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 9th Standard CBSE Mathematics

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Std: 9th Standard CBSE - Mathematics

chapter: Statistics - Sample Question Papers

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Questions:

Generic 4

10 x 4 = 40

The mean of 10,12,16,20,p and 26 is 17. Find the value of p.

The mean of 10,12,18,13,x and 17 is 15. Find the value of x.

Calculate mean of first 5 prime numbers.

Find the mean of first 10 multiples of 7?

Draw a histogram and frequency polygon of the following data:

Marks	No.of students
20-30	5
30-40	12
40-50	6
50-60	20
60-70	18
70-80	10
80-90	16
90-100	3

Draw a frequency polygon to represent the following information:

Class	Frequency
25-29	5
30-34	15
35-39	23
40-44	20
45-49	10
50-54	7

The following table gives the performance of 90 students in a mathematics test of 100 marks.

Marks	Number of students
0-20	07
20-30	10
30-40	10
40-50	20
50-60	20
60-70	15
70-above	08
Total	90

Represent the given information with the help of a histogram.

The marks scored by 750 students in examination are given in the form a frequency distribution table.

Marks	No. of students
600-640	16
640-680	45
680-720	156
720-760	284
760-800	172
800-840	59
840-880	18

Draw a histogram to represent the above data.

The following data gives the number (in thousands) of applicants registered with an Employment Exchange during 2005-2010.

Year	No.of applications registered (in thousands)
2005	19
2006	21
2007	23
2008	30
2009	32
2010	36

Construct a bar graph to represent the above data.

10.

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. Find the class size and class intervals.

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Answers Key:

Generic 4

10 x 4 = 40

\(\frac{10+12+16+20+p+26}{6}=17\)
\(\Rightarrow\) 84 + p = 102
\(\Rightarrow\) p = 102 - 84
\(\Rightarrow\) p = 18.

According to the question,
\(\frac {10+12+18+13+x+17}{6}=15\)
\(\Rightarrow\) x + 70 = 90
\(\Rightarrow\) x = 20

First 5 prime numbers are 2,3,5,7,11
Their mean \(= \frac {2+3+5+7+11}{5}=\frac{28}{5}=5.6\)

First 10 multiples of 7 are
7,14,21,28,35,42,49,56,63,70
Their mean
\(\frac {7+14+21+28+35+42+49+56+63+70}{10} = \frac {385}{10}=38.5\)

We shall first make the class intervals continuous. Then, the modified table is as follows:

Class	Class-marks	Frequency
24.5-29.5	27	5
29.5-34.5	32	15
34.5-39.5	37	23
39.5-44.5	42	20
44.5-49.5	47	10
49.5-54.5	52	7
Total		80

Adjusted frequency a class \(\frac {Minimum \ class \ size}{Class \ size}\times {Frequency \ of \ the \ class}\)
Minimum class size = 10

Marks	Number of students	Adjusted frequency
0-20	07	\(\frac {10}{20}\times 7 = 3.5\)
20-30	10	\(\frac {10}{10}\times 10 = 10\)
30-40	10	\(\frac {10}{10}\times 10 = 10\)
40-50	20	\(\frac {10}{10}\times 20 = 20\)
50-60	20	\(\frac {10}{10}\times 20 = 20\)
60-70	15	\(\frac {10}{10}\times 15 = 15\)
70-80	08	\(\frac {10}{10}\times 08 = 08\)

10.

Class size = 114 -104 = 10
\(\frac {10}{2}=5\)
The class intervals are
104-5___104+5, i.e., 99-109;
114-5___ 114+5, i.e, 109-119;
124-5___ 124+5, i.e., 119-129;
134-5___ 134+5, i.e., 129-139;
144-5___ 144+5, i.e., 139-149;
154-5___ 154+5, i.e., 149-159;
164-5___ 159-169.